我正在尝试将任何请求映射到
目前,我有一个
/views/node_modules/*
的路径转换为Spring项目中的/resources/angular_resources/*
文件夹。我该如何实现?目前,我有一个
applicationContext.xml
文件,其内容如下:<context:component-scan
base-package="fomoapp.domain, fomoapp.dao, fomoapp.service" />
<!-- Root Context: defines shared resources visible to all other web components -->
<mvc:resources mapping="/resources/**" location="/resources/" />
<mvc:resources mapping="/views/node_modules/**" location="/resources/angular_resources/" />
<mvc:default-servlet-handler/>
完整的web.xml
:
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>classpath*:/META-INF/spring/applicationContext.xml
classpath*:/META-INF/spring/applicationContext-security.xml
</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener
</listener-class>
</listener>
<filter>
<filter-name>springSecurityFilterChain</filter-name>
<filter-class>org.springframework.web.filter.DelegatingFilterProxy
</filter-class>
</filter>
<filter-mapping>
<filter-name>springSecurityFilterChain</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<servlet>
<servlet-name>fomoapp</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring/fomoapp-config.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>fomoapp</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>default</servlet-name>
<url-pattern>*.css</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>default</servlet-name>
<url-pattern>*.js</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>default</servlet-name>
<url-pattern>/views/node_modules/</url-pattern>
</servlet-mapping>
我尝试了这里提供的解决方案:在<mvc:resources/>中使用绝对路径而不是相对于Spring Servlet映射的路径
但是它似乎并没有起作用。
web.xml
。 - Nikita Vlasenkoviews/node_modules
)映射到resources
文件夹内的一个文件夹。 - Nikita Vlasenko