我自己有这个需求,而最简单粗暴的方法是:
def unzip(file, dir):
zips = zipfile.ZipFile(file)
for info in zips.infolist():
info.filename = info.filename.encode("cp437").decode("shift-jis")
print("Extracting: " + info.filename.encode(sys.stdout.encoding,errors='replace').decode(sys.stdout.encoding))
zips.extract(info,dir)
print("")
ZipFile
似乎将所有文件名在内部都视为 DOS(代码页 437)。与 Python 2 不同,Python 3 将所有字符串都存储为某种 UTF。因此,我们将文件名转换为字节数组,并将原始字节字符串解码为 shift-JIS,以获取最终文件名。
print
行执行类似的操作,但是针对 stdout
的默认编码进行转换。这可以防止在 Windows 上发生错误,因为它的终端几乎从不支持 Unicode。(但是,如果支持,则应正确显示名称。)
这对于一些 zip 文件效果很好,直到出现问题...
Traceback (most recent call last):
File "jp\j-unzip.py", line 73, in <module>
unzip(archname,archpath)
File "jp\j-unzip.py", line 68, in unzip
info.filename = info.filename.encode("cp437").decode("shift-jis")
UnicodeDecodeError: 'shift_jis' codec can't decode byte 0x8f in position 28: illegal multibyte sequence
额外内容!这个问题需要一些思考才能解决,但问题在于一些有效的Shift-JIS字符包含反斜杠,而ZipFile将其转换为正斜杠!例如,十在Shift-JIS中编码为8F 5C
。这被转换为8F 2F
,这是一个非法序列。以下(可能过于复杂)的代码检查此条件是否发生错误,并尝试修复它。但也许还有其他字符会出现这种情况,而序列是有效的,因此您会得到错误的字符而不是错误。 :(
def convert_filename(inname):
err_ctr=0
keep_going = True
trans_filename = bytearray(inname.encode("cp437"))
while keep_going:
keep_going = False
try:
outname = trans_filename.decode("shift-jis")
except UnicodeDecodeError as e:
keep_going = True
if e.args[4]=="illegal multibyte sequence":
p0, p1 = e.args[2], e.args[3]
print("Trying to fix encoding error at positions " + str(p0) +", "+ str(p1) + " caused by shift-jis sequence " + hex(trans_filename[p0]) +", "+ hex(trans_filename[p1]) )
if (trans_filename[p0]>127 and trans_filename[p1] == 0x2f):
trans_filename[p1] = 0x5c
else:
print("Don't know how to fix this error. Quitting. :(")
raise e
err_ctr = err_ctr + 1
print("This is error #" + str(err_ctr) + " for this filename.")
else:
raise e
if err_ctr>50:
print("More than 50 iterations. Are we stuck in an endless loop? Quitting...")
sys.exit(1)
return outname
def unzip(file, dir):
zips = zipfile.ZipFile(file)
for info in zips.infolist():
info.filename = convert_filename(info.filename)
print("Extracting: " + info.filename.encode(sys.stdout.encoding,errors='replace').decode(sys.stdout.encoding))
zips.extract(info,dir)
print("")