Ansible - 检查项目是否在列表中

Question

我希望对比两个列表-一个包含所有可用选项，另一个包含要选择的特定选项。

例如，我有两个列表：

FullList:
  - name: "Test1"
    value1: "blabla123"
    value2: "someothervalue"
  - name: "Test2"
    value1: "blsdfsdfasfabla"
    value2: "someothervalue"
  - name: "Test3"
    value1: "sdjfbhsadbfv"
    value2: "someothervalue"
  - name: "Test4"
    value1: "sdjkfnsjkf"
    value2: "sdjkfnsjkf"

它包含所有可用元素及其属性。

而我有第二个列表，其中包含特定的键来从完整列表中选择项。

List1:
  - "Test2"
  - "Test3"

我希望从FullList中获取与List1相同的元素。

即，我期望获得：

Result:
  - name: "Test2"
    value1: "blsdfsdfasfabla"
    value2: "someothervalue"
  - name: "Test3"
    value1: "sdjfbhsadbfv"
    value2: "someothervalue"

任何帮助都将不胜感激！

- user41995

Answer 1

使用filter selectattr和test in。例如，

  Result: "{{ FullList|selectattr('name', 'in', List1) }}"

给出了预期的结果

  Result:
    - {name: Test2, value1: blsdfsdfasfabla, value2: someothervalue}
    - {name: Test3, value1: sdjfbhsadbfv, value2: someothervalue}

---

Example of a complete playbook for testing

- hosts: all
  
  vars:

    FullList:
      - {name: Test1, value1: blabla123, value2: someothervalue}
      - {name: Test2, value1: blsdfsdfasfabla, value2: someothervalue}
      - {name: Test3, value1: sdjfbhsadbfv, value2: someothervalue}
      - {name: Test4, value1: sdjkfnsjkf, value2: sdjkfnsjkf}      
    List1: [Test2, Test3]

    Result: "{{ FullList|selectattr('name', 'in', List1) }}"

  tasks:

    - debug:
        var: Result|to_yaml
      run_once: true

- Vladimir Botka

---

非常感谢您，弗拉基米尔！ - user41995

Answer 2

请按照以下步骤尝试打印：

  tasks:
  - debug:
     msg : "{{ item }}"
    when: item.name in List1
    loop: "{{FullList}}"

要保存到变量中，请按以下方式使用

  - name: test
    set_fact:
     test: "{{ item }}"
    when: item.name in List1
    loop: "{{FullList}}"

- Smily