FFmpeg复制流而不转码

3
我试图将多个文件中的所有流复制到一个文件中,而不需要对流进行转码。这通常可以使用ffmpeg实用程序来完成:ffmpeg -i“file_with_audio.mp4” -i“file_with_video.mp4” -c copy -shortest file_with_audio_and_video.mp4 以下是代码:
int ffmpegOpenInputFile(const char* filename, AVFormatContext **ic) {

    int ret;
    unsigned int i;

    *ic = avformat_alloc_context();
    if (!(*ic))
        return -1; // Couldn't allocate input context

    if((ret = avformat_open_input(ic, filename, NULL, NULL)) < 0)
        return ret; // Couldn't open file

    // Get format info (retrieve stream information)
    if ((ret = avformat_find_stream_info(*ic, NULL)) < 0)
        return ret; // Couldn't find stream information

    for (int i = 0; i < (*ic)->nb_streams; i++) {
        AVStream *stream;
        AVCodecContext *codec_ctx;
        stream = (*ic)->streams[i];
        codec_ctx = stream->codec;
        /* Reencode video & audio and remux subtitles etc. */
        if (codec_ctx->codec_type == AVMEDIA_TYPE_VIDEO
            || codec_ctx->codec_type == AVMEDIA_TYPE_AUDIO) {
            /* Open decoder */
            ret = avcodec_open2(codec_ctx,
                                avcodec_find_decoder(codec_ctx->codec_id), NULL);
            if (ret < 0) {
                av_log(NULL, AV_LOG_ERROR, "Failed to open decoder for stream #%u\n", i);
                return ret;
            }
        }
    }

    // Dump information about file onto standard error
    av_dump_format(*ic, 0, filename, 0);

    return 0;
}



int main(int argc, char *argv[]) {

    const char *inputFilename1 = "/avfiles/video_input.mp4";
    const char *inputFilename2 = "/avfiles/audio_input.mp4";
    const char *filename = "/avfiles/out.mp4";

    int ret;

    av_register_all();

    AVFormatContext *ic1 = nullptr;
    AVFormatContext *ic2 = nullptr;
    AVFormatContext *oc = nullptr;

    if ((ret = ffmpegOpenInputFile(inputFilename1, &ic1)) < 0)
        return ret;  // and free resources and

    if ((ret = ffmpegOpenInputFile(inputFilename2, &ic2)) < 0)
        return ret;  // and free resources and

    AVOutputFormat *outfmt = av_guess_format(NULL, filename, NULL);
    if (outfmt == NULL)
        return -1;  // Could not guess output format

    avformat_alloc_output_context2(&oc, outfmt, NULL, filename);
    if (!oc)
        return AVERROR_UNKNOWN;  // Could not create output context

    // populate input streams from all input files
    AVStream **input_streams = NULL;
    int nb_input_streams = 0;
    for (int i = 0; i < ic1->nb_streams; i++) {
        input_streams = (AVStream **) grow_array(input_streams, sizeof(*input_streams), &nb_input_streams,
                                                 nb_input_streams + 1);
        input_streams[nb_input_streams - 1] = ic1->streams[i];
    }
    for (int i = 0; i < ic2->nb_streams; i++) {
        input_streams = (AVStream **) grow_array(input_streams, sizeof(*input_streams), &nb_input_streams,
                                                 nb_input_streams + 1);
        input_streams[nb_input_streams - 1] = ic2->streams[i];
    }

    for (int i = 0; i < nb_input_streams; i++) {
        AVStream *ist = input_streams[i];  // could be named 'm_in_vid_strm'

        // if output context has video codec support and current input stream is video
        if (/*oc->video_codec_id*/ oc->oformat->video_codec != AV_CODEC_ID_NONE && ist != NULL
                                   && ist->codec->codec_type == AVMEDIA_TYPE_VIDEO) {

            AVCodec *out_vid_codec = avcodec_find_encoder(oc->oformat->video_codec);
            if (NULL == out_vid_codec)
                return -1;  // Couldn't find video encoder

            AVStream *m_out_vid_strm = avformat_new_stream(oc, out_vid_codec);
            if (NULL == m_out_vid_strm)
                return -1;  // Couldn't output video stream

            m_out_vid_strm->id = 0;  // XXX:

            ret = avcodec_copy_context(m_out_vid_strm->codec, ist->codec);
            if (ret < 0)
                return ret;  // Failed to copy context

        }

        // if output context has audio codec support and current input stream is audio
        if (/*oc->audio_codec_id*/ oc->oformat->audio_codec != AV_CODEC_ID_NONE && ist != NULL
                                   && ist->codec->codec_type == AVMEDIA_TYPE_AUDIO) {

            AVCodec *out_aud_codec = avcodec_find_encoder(oc->oformat->audio_codec);
            if (nullptr == out_aud_codec)
                return -1;  // couldn't find audio codec

            AVStream *m_out_aud_strm = avformat_new_stream(oc, out_aud_codec);
            if (nullptr == m_out_aud_strm)
                return -1;  // couldn't allocate audio out stream

            ret = avcodec_copy_context(m_out_aud_strm->codec, ist->codec);
            if (ret < 0)
                return ret;  // couldn't copy context

        }
    }

    // finally output header
    if (!(oc->flags & AVFMT_NOFILE)) {

        ret = avio_open(&oc->pb, filename, AVIO_FLAG_WRITE);
        if (ret < 0)
            return ret;  // Could not open output file

        av_dump_format(oc, 0, filename, 1);

        ret = avformat_write_header(oc, NULL);
        if (ret < 0)
            return ret; // Error occurred when opening output file

    }

    return 0;

}

avformat_write_header(oc, NULL); 总是返回错误,并且我看到了这样的信息:

[mp4 @ 0x7f84ec900a00] Using AVStream.codec.time_base as a timebase hint to the muxer is deprecated. Set AVStream.time_base instead.
[mp4 @ 0x7f84ec900a00] Tag avc1/0x31637661 incompatible with output codec id '28' ([33][0][0][0])

但输入和输出流匹配:

Input streams from 2 files:
Stream #0:0(und): Video: h264 (High) (avc1 / 0x31637661), yuv420p, 1920x1080 [SAR 1:1 DAR 16:9], 2834 kb/s, 23.98 fps, 23.98 tbr, 90k tbn, 47.95 tbc (default)
Stream #0:0(und): Audio: aac (LC) (mp4a / 0x6134706D), 44100 Hz, stereo, fltp, 125 kb/s (default)

Output #0, mp4, to '/Users/alex/Workspace/_qt/tubisto/avfiles/out.mp4':
    Stream #0:0: Video: h264 (libx264) (avc1 / 0x31637661), yuv420p, 1920x1080 [SAR 1:1 DAR 16:9], q=2-31, 2834 kb/s, 47.95 tbc
    Stream #0:1: Audio: aac (libvo_aacenc) (mp4a / 0x6134706D), 44100 Hz, stereo, fltp, 125 kb/s

为什么会出现不兼容输出编解码器的错误? 我的代码有什么问题,如何使其能够将所有输入文件的所有流复制到输出文件中?

1个回答

5
原因是因为您没有正确设置编码器的codec_tag
您应该设置正确的codec_tag,或将codec_tag设置为0,让复用器为您处理。
以下是如何操作的示例代码。
AVFormatContext *ofmt_ctx; // todo
AVCodec *oc; // todo

AVStream *stream = avformat_new_stream(ofmt_ctx, oc);

if (stream != NULL) {
    // ...
    unsigned int tag = 0;
    // for ffmpeg new api 3.x
    AVCodecParameters *parameters = stream->codecpar;
    if (av_codec_get_tag2(ofmt_ctx->oformat->codec_tag, oc->id, &tag) == 0) {
        av_log(NULL, AV_LOG_ERROR, "could not find codec tag for codec id %d, default to 0.\n", oc->id);
    }
    parameters->codec_tag = tag;
    stream->codec = avcodec_alloc_context3(oc);
    // more setting for stream->codec
    avcodec_parameters_to_context(stream->codec, parameters);

    // for old ffmpeg version
    stream->codec->codec_tag = tag;
    // ...
}

你救了我... 我试了两天才明白为什么我的“合并”代码在 mp4 上无法工作,将标签设置在目标参数上就解决了! - gabry

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