我需要运行一个单一的LDAP查询，以在根查询中搜索两个特定的组织单位（OU），但我遇到了困难。我尝试了下面的查询，但都不成功：
(|(OU=Staff,DC=my,DC=super,DC=org)(OU=Vendors,DC=my,DC=super,DC=org))
((OU=Staff,DC=my,DC=super,DC=org) | (OU=Vendors,DC=my,DC=super,DC=org))
我的问题是：是否可以在一个LDAP查询中查询多个单个OU？假设这是正确的语法，以便在根LDAP查询中使用此类型的表达式。
ldap://<host>:3268/DC=<my>,DC=<domain>?cn
与您的搜索过滤器一起，例如。
(&(sAMAccountName={0})(&((objectCategory=person)(objectclass=user)(mail=*)(!(userAccountControl:1.2.840.113556.1.4.803:=2))(memberOf:1.2.840.113556.1.4.1941:=CN=<some-special-nested-group>,OU=<ou3>,OU=<ou2>,OU=<ou1>,DC=<dc3>,DC=<dc2>,DC=<dc1>))))
ldap://<host>/DC=<my>,DC=<domain>
ldap://<host>:389/DC=<my>,DC=<domain> (standard port)
ldap://<host>/OU=<someOU>,DC=<my>,DC=<domain>
ldap://<host>/CN=<someCN>,DC=<my>,DC=<domain>
ldap://<host>/(|(OU=<someOU1>)(OU=<someOU2>)),DC=<my>,DC=<domain> (search filters here shouldn't work at all by definition)
以下是我在研究过程中发现的其他相关线程，它们大多没有什么帮助：
以下是我们匿名化后的Tomcat LDAP配置，希望对您有所帮助（路径为/var/lib/tomcat7/webapps/jasperserver/WEB-INF/applicationContext-externalAUTH-LDAP.xml）：
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.1.xsd">
<!-- ############ LDAP authentication ############ - Sample configuration
of external authentication via an external LDAP server. -->
<bean id="proxyAuthenticationProcessingFilter"
class="com.jaspersoft.jasperserver.api.security.externalAuth.BaseAuthenticationProcessingFilter">
<property name="authenticationManager">
<ref local="ldapAuthenticationManager" />
</property>
<property name="externalDataSynchronizer">
<ref local="externalDataSynchronizer" />
</property>
<property name="sessionRegistry">
<ref bean="sessionRegistry" />
</property>
<property name="internalAuthenticationFailureUrl" value="/login.html?error=1" />
<property name="defaultTargetUrl" value="/loginsuccess.html" />
<property name="invalidateSessionOnSuccessfulAuthentication"
value="true" />
<property name="migrateInvalidatedSessionAttributes" value="true" />
</bean>
<bean id="proxyAuthenticationSoapProcessingFilter"
class="com.jaspersoft.jasperserver.api.security.externalAuth.DefaultAuthenticationSoapProcessingFilter">
<property name="authenticationManager" ref="ldapAuthenticationManager" />
<property name="externalDataSynchronizer" ref="externalDataSynchronizer" />
<property name="invalidateSessionOnSuccessfulAuthentication"
value="true" />
<property name="migrateInvalidatedSessionAttributes" value="true" />
<property name="filterProcessesUrl" value="/services" />
</bean>
<bean id="proxyRequestParameterAuthenticationFilter"
class="com.jaspersoft.jasperserver.war.util.ExternalRequestParameterAuthenticationFilter">
<property name="authenticationManager">
<ref local="ldapAuthenticationManager" />
</property>
<property name="externalDataSynchronizer" ref="externalDataSynchronizer" />
<property name="authenticationFailureUrl">
<value>/login.html?error=1</value>
</property>
<property name="excludeUrls">
<list>
<value>/j_spring_switch_user</value>
</list>
</property>
</bean>
<bean id="proxyBasicProcessingFilter"
class="com.jaspersoft.jasperserver.api.security.externalAuth.ExternalAuthBasicProcessingFilter">
<property name="authenticationManager" ref="ldapAuthenticationManager" />
<property name="externalDataSynchronizer" ref="externalDataSynchronizer" />
<property name="authenticationEntryPoint">
<ref local="basicProcessingFilterEntryPoint" />
</property>
</bean>
<bean id="proxyAuthenticationRestProcessingFilter"
class="com.jaspersoft.jasperserver.api.security.externalAuth.DefaultAuthenticationRestProcessingFilter">
<property name="authenticationManager">
<ref local="ldapAuthenticationManager" />
</property>
<property name="externalDataSynchronizer">
<ref local="externalDataSynchronizer" />
</property>
<property name="filterProcessesUrl" value="/rest/login" />
<property name="invalidateSessionOnSuccessfulAuthentication"
value="true" />
<property name="migrateInvalidatedSessionAttributes" value="true" />
</bean>
<bean id="ldapAuthenticationManager" class="org.springframework.security.providers.ProviderManager">
<property name="providers">
<list>
<ref local="ldapAuthenticationProvider" />
<ref bean="${bean.daoAuthenticationProvider}" />
<!--anonymousAuthenticationProvider only needed if filterInvocationInterceptor.alwaysReauthenticate
is set to true <ref bean="anonymousAuthenticationProvider"/> -->
</list>
</property>
</bean>
<bean id="ldapAuthenticationProvider"
class="org.springframework.security.providers.ldap.LdapAuthenticationProvider">
<constructor-arg>
<bean
class="org.springframework.security.providers.ldap.authenticator.BindAuthenticator">
<constructor-arg>
<ref local="ldapContextSource" />
</constructor-arg>
<property name="userSearch" ref="userSearch" />
</bean>
</constructor-arg>
<constructor-arg>
<bean
class="org.springframework.security.ldap.populator.DefaultLdapAuthoritiesPopulator">
<constructor-arg index="0">
<ref local="ldapContextSource" />
</constructor-arg>
<constructor-arg index="1">
<value></value>
</constructor-arg>
<property name="groupRoleAttribute" value="cn" />
<property name="convertToUpperCase" value="true" />
<property name="rolePrefix" value="ROLE_" />
<property name="groupSearchFilter"
value="(&(member={0})(&(objectCategory=Group)(objectclass=group)(cn=my-nested-group-name)))" />
<property name="searchSubtree" value="true" />
<!-- Can setup additional external default roles here <property name="defaultRole"
value="LDAP"/> -->
</bean>
</constructor-arg>
</bean>
<bean id="userSearch"
class="org.springframework.security.ldap.search.FilterBasedLdapUserSearch">
<constructor-arg index="0">
<value></value>
</constructor-arg>
<constructor-arg index="1">
<value>(&(sAMAccountName={0})(&((objectCategory=person)(objectclass=user)(mail=*)(!(userAccountControl:1.2.840.113556.1.4.803:=2))(memberOf:1.2.840.113556.1.4.1941:=CN=my-nested-group-name,OU=ou3,OU=ou2,OU=ou1,DC=dc3,DC=dc2,DC=dc1))))
</value>
</constructor-arg>
<constructor-arg index="2">
<ref local="ldapContextSource" />
</constructor-arg>
<property name="searchSubtree">
<value>true</value>
</property>
</bean>
<bean id="ldapContextSource"
class="com.jaspersoft.jasperserver.api.security.externalAuth.ldap.JSLdapContextSource">
<constructor-arg value="ldap://myhost:3268/DC=dc3,DC=dc2,DC=dc1?cn" />
<!-- manager user name and password (may not be needed) -->
<property name="userDn" value="CN=someuser,OU=ou4,OU=1,DC=dc3,DC=dc2,DC=dc1" />
<property name="password" value="somepass" />
<!--End Changes -->
</bean>
<!-- ############ LDAP authentication ############ -->
<!-- ############ JRS Synchronizer ############ -->
<bean id="externalDataSynchronizer"
class="com.jaspersoft.jasperserver.api.security.externalAuth.ExternalDataSynchronizerImpl">
<property name="externalUserProcessors">
<list>
<ref local="externalUserSetupProcessor" />
<!-- Example processor for creating user folder -->
<!--<ref local="externalUserFolderProcessor"/> -->
</list>
</property>
</bean>
<bean id="abstractExternalProcessor"
class="com.jaspersoft.jasperserver.api.security.externalAuth.processors.AbstractExternalUserProcessor"
abstract="true">
<property name="repositoryService" ref="${bean.repositoryService}" />
<property name="userAuthorityService" ref="${bean.userAuthorityService}" />
<property name="tenantService" ref="${bean.tenantService}" />
<property name="profileAttributeService" ref="profileAttributeService" />
<property name="objectPermissionService" ref="objectPermissionService" />
</bean>
<bean id="externalUserSetupProcessor"
class="com.jaspersoft.jasperserver.api.security.externalAuth.processors.ExternalUserSetupProcessor"
parent="abstractExternalProcessor">
<property name="userAuthorityService">
<ref bean="${bean.internalUserAuthorityService}" />
</property>
<property name="defaultInternalRoles">
<list>
<value>ROLE_USER</value>
</list>
</property>
<property name="organizationRoleMap">
<map>
<!-- Example of mapping customer roles to JRS roles -->
<entry>
<key>
<value>ROLE_MY-NESTED-GROUP-NAME</value>
</key>
<!-- JRS role that the <key> external role is mapped to -->
<value>ROLE_USER</value>
</entry>
</map>
</property>
</bean>
<!--bean id="externalUserFolderProcessor" class="com.jaspersoft.jasperserver.api.security.externalAuth.processors.ExternalUserFolderProcessor"
parent="abstractExternalProcessor"> <property name="repositoryService" ref="${bean.unsecureRepositoryService}"/>
</bean -->
<!-- ############ JRS Synchronizer ############ -->
Attribute Operator Value的表达式组成。organizationalPerson类继承的名为OU的属性。您可以为某些用户设置它（它不是自动的，并且如果移动用户，它将不会被维护），并为其他用户设置“vendors”，然后使用过滤器：(&(objectCategory=person)(|(ou=staff)(ou=vendors)))
ou:dn:=<val>语法对于提问者的问题，解决方法如下：
ldapsearch -b "DC=my,DC=super,DC=org" <other_options> "(|(ou:dc:=Staff)(ou:dc:=Vendors))"
原则上，您的情况比较棘手，因为OU值不会出现在用户的ldapsearch输出中-- OU值是DN的一部分。
例如，在这里进行的搜索结果：
[root@pg data]# ldapsearch -H "ldap://ldap-service" -D "cn=admin,dc=example,dc=org" -w admin -b"DC=example,DC=org" cn=testuser2
# extended LDIF
#
# LDAPv3
# base <DC=example,DC=org> with scope subtree
# filter: cn=testuser2
# requesting: ALL
#
# testuser2, AU, IIQ, example.org
dn: cn=testuser2,ou=AU,ou=IIQ,dc=example,dc=org
cn: testuser2
displayName: pgtest
gidNumber: 500
givenName: testuser2
homeDirectory: /home/testuser2
loginShell: /bin/sh
objectClass: inetOrgPerson
objectClass: posixAccount
objectClass: top
userPassword:: e01ENX1GMnFxVVpDTjh4VVJveGg5bkJBcGF3PT0=
sn: testuser2
uidNumber: 1012
uid: testuser2
# search result
search: 2
result: 0 Success
# numResponses: 2
# numEntries: 1
没有ou：行，因为OU属于dn：行。因此，如果您在搜索中添加一个ou，您会看到它是requesting: ou而不是requesting: ALL，但不会列出任何属性：
[root@pg data]# ldapsearch -H "ldap://ldap-service" -D "cn=admin,dc=example,dc=org" -w admin -b"DC=example,DC=org" cn=testuser2 ou
# extended LDIF
#
# LDAPv3
# base <DC=example,DC=org> with scope subtree
# filter: cn=testuser2
# requesting: ou
#
# testuser2, AU, IIQ, example.org
dn: cn=testuser2,ou=AU,ou=IIQ,dc=example,dc=org
# search result
search: 2
result: 0 Success
# numResponses: 2
# numEntries: 1
在OU上搜索会给你结果，但它们只是OU对象，而不是用户本身：
[root@pg data]# ldapsearch -H "ldap://ldap-service" -D "cn=admin,dc=example,dc=org" -w admin -b"DC=example,DC=org" "(|(OU=IN)(OU=AU))"
# extended LDIF
#
# LDAPv3
# base <DC=example,DC=org> with scope subtree
# filter: (|(OU=IN)(OU=AU))
# requesting: ALL
#
# IN, example.org
dn: ou=IN,dc=example,dc=org
ou: IN
objectClass: organizationalUnit
objectClass: top
# AU, example.org
dn: ou=AU,dc=example,dc=org
ou: AU
objectClass: organizationalUnit
objectClass: top
# IN, IIQ, example.org
dn: ou=IN,ou=IIQ,dc=example,dc=org
objectClass: organizationalUnit
objectClass: top
ou: IN
# AU, IIQ, example.org
dn: ou=AU,ou=IIQ,dc=example,dc=org
ou: AU
objectClass: organizationalUnit
objectClass: top
# search result
search: 2
result: 0 Success
# numResponses: 5
# numEntries: 4
然而，ldapsearch 允许您使用 ou:dn:=<val> 语法提取 DN 的部分内容：
[root@pg data]# ldapsearch -H "ldap://ldap-service" -D "cn=admin,dc=example,dc=org" -w admin -b"DC=example,DC=org" "(&(displayname=pgtest)(|(ou:dn:=IN)(ou:dn:=AU)))" cn displayname
# extended LDIF
#
# LDAPv3
# base <DC=example,DC=org> with scope subtree
# filter: (&(displayname=pgtest)(|(ou:dn:=IN)(ou:dn:=AU)))
# requesting: cn displayname
#
# testuser3, AU, example.org
dn: cn=testuser3,ou=AU,dc=example,dc=org
cn: testuser3
displayName: pgtest
# testuser4, IN, example.org
dn: cn=testuser4,ou=IN,dc=example,dc=org
cn: testuser4
displayName: pgtest
# testuser2, AU, IIQ, example.org
dn: cn=testuser2,ou=AU,ou=IIQ,dc=example,dc=org
cn: testuser2
displayName: pgtest
# testuser1, IN, IIQ, example.org
dn: cn=testuser1,ou=IN,ou=IIQ,dc=example,dc=org
cn: testuser1
displayName: pgtest
# testuser14, IN, example.org
dn: cn=testuser14,ou=IN,dc=example,dc=org
cn: testuser14
displayName: pgtest
# search result
search: 2
result: 0 Success
# numResponses: 6
# numEntries: 5
与LDAP专家交谈后，发现这种方式不可行。一个查询无法搜索多个DC或OU。
您有以下选项：
- 运行多个查询并解析结果。
- 使用过滤器根据不同的属性（如AD组或名称）查找所需的用户/对象。
objectClasses允许ou属性，则可以在搜索过滤器中使用ou属性。当然，这需要将ou属性添加到相关条目中。这可能是一个有效的解决方案，因为AD不支持可扩展匹配过滤器的出色建议。 - Terry Gardner