Swift 3中如何处理启动选项以响应通知？遇到语法问题。

Question

我正在尝试处理启动选项，并在接收到远程通知后点击打开特定的视图控制器（Swift 3）。我看到了类似的问题，例如这里，但没有针对新的Swift 3实现的解决方案。我在AppDelegate.swift中看到了一个类似的问题，在didFinishLaunchingWithOptions中添加了以下内容：

    var localNotif = (launchOptions[UIApplicationLaunchOptionsRemoteNotificationKey] as! String)
if localNotif {
    var itemName = (localNotif.userInfo!["aps"] as! String)
    print("Custom: \(itemName)")
}
else {
    print("//////////////////////////")
}

但是 Xcode 给了我这个错误:

Type '[NSObject: AnyObject]?' has no subscript members

我也尝试了这个：

   if let launchOptions = launchOptions {
        var notificationPayload: NSDictionary = launchOptions[UIApplicationLaunchOptionsRemoteNotificationKey] as NSDictionary!

    }

然后我收到了这个错误：

error: ambiguous reference to member 'subscript'

我之前在类似的代码中使用字典键获取值时，遇到了类似的错误，不得不替换代码并安全地解包字典。但在这里似乎行不通。希望能得到帮助。谢谢。

- TheBen

Answer 1

苹果在Swift 3中进行了许多更改，这是其中之一。

编辑：这也适用于Swift 4。

func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplicationLaunchOptionsKey: Any]?) -> Bool {
    //Launched from push notification
    let remoteNotif = launchOptions?[UIApplicationLaunchOptionsKey.remoteNotification] as? [String: Any]
    if remoteNotif != nil {
        let aps = remoteNotif!["aps"] as? [String:AnyObject]
        NSLog("\n Custom: \(String(describing: aps))")
    }
    else {
        NSLog("//////////////////////////Normal launch")
    }
}

Swift 5：

func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplication.LaunchOptionsKey: Any]?) -> Bool {
    //Launched from push notification
    guard let options = launchOptions,
        let remoteNotif = options[UIApplication.LaunchOptionsKey.remoteNotification] as? [String: Any]
        else {
            return
    }
    let aps = remoteNotif["aps"] as? [String: Any]
    NSLog("\n Custom: \(String(describing: aps))")
    
    handleRemoteNotification(remoteNotif)
}

更多关于LaunchOptionsKey的内容请阅读苹果公司的文档。

- Adeel Miraj

---

我仍然收到错误信息，成员下标的引用不明确！ - TheBen

我的错，有一个错误。现在请再试一次。 - Adeel Miraj

嗯，谢谢，但你确定更新了你的回复吗？看起来还是一样的。 - TheBen

是的，我做了一些更改。它们非常微小，所以不太明显。 - Adeel Miraj

正如我在上面的答案中提到的，didfinishwithoptions方法的整个签名已经改变。再次感谢您的评论。 - TheBen

Answer 2

结果发现整个方法签名都已经改变，当我实现了新的签名后一切正常。下面是代码。

新的didFinishLaunchingWithOptions方法：

func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplicationLaunchOptionsKey : Any]? = nil) -> Bool {



//and then 
 if launchOptions?[UIApplicationLaunchOptionsKey.remoteNotification] != nil {


// Do what you want to happen when a remote notification is tapped.


}

}

希望这可以帮助到你。

- TheBen

Answer 3

Swift 4

// Check if launched from the remote notification and application is close
 if let remoteNotification = launchOptions?[.remoteNotification] as?  [AnyHashable : Any] {
            // Do what you want to happen when a remote notification is tapped.
            let aps = remoteNotification["aps" as String] as? [String:AnyObject]
            let apsString =  String(describing: aps)
            debugPrint("\n last incoming aps: \(apsString)")
    }

- Amr Angry

---

如何在 didReceiveRemoteNotification 函数中传递此通知对象？ - Vinoth Vino

抱歉，我不太明白你的意思，请详细说明一下，这样我才能帮助你。 - Amr Angry

Answer 4

if let remoteNotif = launchOptions?[UIApplicationLaunchOptionsKey.remoteNotification] as? [String: Any] {
       if let notification = remoteNotif["aps"] as? [AnyHashable : Any] {
               //handle PN
       }
}

- Svitlana

Answer 5

Swift 3：

        if let notification = launchOptions?[.localNotification] as? NSDictionary{

            #if DEBUG
                print("iOS9 didFinishLaunchingWithOptions notification\n \(notification)")
            #endif

- ingconti