我正在努力从过程式编程跳转到面向对象的编程风格,如果我的代码不整洁或有缺陷,请多多包涵 - 这里我通过jQuery将一些帖子传递给一个类,以在用户勾选复选框时更新记录:
这是数据库连接
class db {
private $host ;
private $username;
private $password;
private $dbname;
protected function conn()
{
$this->host = "localhost";
$this->username = "root";
$this->password = "";
$this->dbname = "mytest";
$db = new mysqli($this->host, $this->username, $this->password, $this->dbname);
if($db->connect_errno > 0){
die('Unable to connect to database [' . $db->connect_error . ']');
}
return $db;
}
}
这是更新类:
class updOrders extends db {
public $pid;
public $proc;
public function __construct()
{
$this->pid = isset($_POST['pid']) ? $_POST['pid'] : 0;
$this->proc = isset($_POST['proc']) ? $_POST['proc'] : 1;
// $stmt = $this->conn()->query("UPDATE tblorderhdr SET completed = ".$this->proc." WHERE orderid = ".$this->pid);
$stmt = $this->conn()->prepare("UPDATE tblorderhdr SET completed = ? WHERE orderid = ?");
$stmt->bind_param('ii', $this->proc, $this->pid);
$stmt->execute();
if($stmt->error)
{
$err = $stmt->error ;
} else {
$err = 'ok';
}
/* close statement */
$stmt->close();
echo json_encode($err);
}
}
$test = new updOrders;
当我将 prepare 语句注释掉并直接运行查询语句时(已注释),它会更新,但当我尝试将其作为 prepare 语句运行时,会返回错误“MySQL服务器已断开连接”。