type
....
TTimeLog = type Int64;
^^^^
第二个
type
关键字(在Int64
前面)的目的是什么?type
....
TTimeLog = type Int64;
^^^^
type
关键字(在Int64
前面)的目的是什么?When you declare a type that is identical to an existing type, the compiler treats the new type identifier as an alias for the old one. Thus, given the declarations:
type TValue = Real; var X: Real; Y: TValue;
X and Y are of the same type; at runtime, there is no way to distinguish TValue from Real. This is usually of little consequence, but if your purpose in defining a new type is to utilize runtime type information, for example, to associate a property editor with properties of a particular type - the distinction between 'different name' and 'different type' becomes important. In this case, use the syntax:
type newTypeName = type KnownType
For example:
type TValue = type Real;
forces the compiler to create a new, distinct type called TValue.
For var parameters, types of formal and actual must be identical. For example:
type TMyType = type Integer; procedure p(var t:TMyType); begin end; procedure x; var m: TMyType; i: Integer; begin p(m); // Works p(i); // Error! Types of formal and actual must be identical. end;
此主题
中有所描述。 - TLama