从Django 1.4.3的媒体文件夹下载已上传的文件

Question

I am using django to design basic web pages that handle file uploading and downloading to/from the media folder. The files are successfully uploaded to the media folder and downloaded, but an underscore is added to the end of the file name, such as "file_one.pdf_", "file_two.pdf_", "file_three.txt_", etc.

Below are my codes.

urls.py

urlpatterns = patterns('',
             url(r'^upload$', 'learn_django.views.upload'),
             url(r'^files_list$', 'learn_django.views.files_list'),
             url(r'^download/(?P<file_name>.+)$', 'learn_django.views.download'),
)
if settings.DEBUG:
    urlpatterns = patterns('',
    url(r'^media/(?P<path>.*)$', 'django.views.static.serve',{'document_root': settings.MEDIA_ROOT, 'show_indexes': True}),
) + urlpatterns

views.py

def upload(request):
    ......
    ....
    return render_to_response('uploads_form.html', {'form': form},context_instance=RequestContext(request))


def files_list(request):
    return render_to_response('files_list.html',{'total_files':os.listdir(settings.MEDIA_ROOT),'path':settings.MEDIA_ROOT},context_instance=RequestContext(request))

def download(request,file_name):
    file_path = settings.MEDIA_ROOT +'/'+ file_name
    file_wrapper = FileWrapper(file(file_path,'rb'))
    file_mimetype = mimetypes.guess_type(file_path)
    response = HttpResponse(file_wrapper, content_type=file_mimetype )
    response['X-Sendfile'] = file_path
    response['Content-Length'] = os.stat(file_path).st_size
    response['Content-Disposition'] = 'attachment; filename=%s/' % smart_str(file_name) 
    return response

files_list.html

<table border="1" colspan="2" width="100%">
   <tr>
     <th width="60%">File</td>
     <th width="40%">Download</td> 
   </tr>
 {% for file in total_files %}
   <tr>
     <td width="60%">{{file}}</td>
     <td width="40%" align="center"><a href="/download/{{file}}" style="text-decoration:None">Download here</a></td>
   </tr>
 {% endfor %}  
</table>

在上述代码中，当文件成功上传到媒体中时，它将通过files_list视图函数重定向到files_list.html，该函数以表格形式显示文件的总数，并在每个文件名旁边提供下载链接。

因此，当我们单击下载锚链接时，将通过执行download函数下载相应的文件。

因此，文件正在成功下载，但是在文件名的末尾添加了下划线_，例如file_one.pdf_，file_two.pdf_，file_three.txt_等。

因此，请问有谁能告诉我，我的下载函数代码有什么问题，为什么会在文件名后面添加下划线，并且如何从文件名中删除该下划线...

- Shiva Krishna Bavandla

Answer 1

只需在文件名后面删除/。

更改为:

response['Content-Disposition'] = 'attachment; filename=%s/' % smart_str(file_name) 

转换为：

response['Content-Disposition'] = 'attachment; filename=%s' % smart_str(file_name) 

- goromlagche

Answer 2

您的代码是正确的，但是download中有一个多余的字符：

def download(request,file_name):
    file_path = settings.MEDIA_ROOT +'/'+ file_name
    file_wrapper = FileWrapper(file(file_path,'rb'))
    file_mimetype = mimetypes.guess_type(file_path)
    response = HttpResponse(file_wrapper, content_type=file_mimetype )
    response['X-Sendfile'] = file_path
    response['Content-Length'] = os.stat(file_path).st_size
    response['Content-Disposition'] = 'attachment; filename=%s/' % smart_str(file_name) 
    return response

最后一行的文件名属性有一个尾部斜杠(/)：filename=%s/。这导致了问题的发生。去掉这个斜杠，它就能工作了。

- CumaTekin

Answer 3

这些都不是必需的。在HTML中，您可以使用<a download="{video.URL}">来下载媒体文件。

例如：

<button class="btn btn-outline-info">
<a href="{{result.products.full_video.url}}" download="{{result.products.full_video.url}}" style="text-decoration:None" class="footer_link">Download<i class="fa fa-download"></i></a>
</button>

- Chethan H V

Answer 4

我通过替换解决了这个问题

response['Content-Disposition'] = 'attachment; filename=diploma_"' + str(someID) + '.pdf"'

使用

response['Content-Disposition'] = 'attachment; filename="diploma_{}{}"'.format(str(someID),'.pdf')

- Edd

Answer 5

import urllib, mimetypes
from django.http import HttpResponse, Http404, StreamingHttpResponse, FileResponse
import os
from django.conf import settings
from wsgiref.util import FileWrapper

class DownloadFileView(django_views):
    def get(self,request,file_name):
        file_path = settings.MEDIA_ROOT +'/'+ file_name
        file_wrapper = FileWrapper(open(file_path,'rb'))
        file_mimetype = mimetypes.guess_type(file_path)
        response = HttpResponse(file_wrapper, content_type=file_mimetype )
        response['X-Sendfile'] = file_path
        response['Content-Length'] = os.stat(file_path).st_size
        response['Content-Disposition'] = 'attachment; filename=%s/' % str(file_name) 
        return response

- surya

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