ThreadSafeClientConnManager不支持多线程

4
我被要求修复一个位于两个应用程序之间的Servlet。它的目的是将SAML授权请求转换为SAML v2.0 / SAML 1.1并相互转换。因此,它:
  • 从一个应用程序接收HTTP SAML v2.0授权请求
  • 将请求转换为SAML v1.1
  • 将请求发送到第二个应用程序
  • 从第二个应用程序接收SAML v1.1响应
  • 将响应转换为SAML v2.0
  • 将响应发送回第一个应用程序
不要担心SAML的问题,问题在于HTTP方面。代码可以正常工作,但是在负载下性能大打折扣。通过测试,我发现即使代码使用了来自Apache httpcomponents的ThreadSafeClientConnManager,每个命中servlet的请求仍以单线程方式处理。更准确地说,一旦代码到达HTTPClient.execute()方法,第一个创建连接的线程将在其他线程开始工作之前完成整个进程。例如:
  • 同时有15个请求命中servlet
  • servlet生成15个线程来服务请求
  • 所有15个线程都检索其各自的请求数据
  • 所有15个线程都将其各自的数据从SAML v2.0转换为SAML v1.1
  • 线程1调用HTTPClient.execute()
    • 线程1将请求发送到第二个应用程序
    • 线程1从第二个应用程序接收响应
    • 线程1解码响应并将其从SAML v1.1转换为SAML v2.0
    • 线程1将响应发送回第一个应用程序
  • 线程2调用HTTPClient.execute()
  • ...等等...
我在下面包含了代码。从我看到的内容来看,所有必要的项目都存在。有人能看出任何错误或缺失吗?这会防止此servlet同时服务多个请求吗?
public class MappingServlet extends HttpServlet {

private HttpClient client;
private String pdp_url;

public void init() throws ServletException {
    org.opensaml.Configuration.init();
    pdp_url = getInitParameter("pdp_url");

    ThreadSafeClientConnManager cm = new ThreadSafeClientConnManager();
    HttpRoute route = new HttpRoute(new HttpHost(pdp_url));
    cm.setDefaultMaxPerRoute(100);
    cm.setMaxForRoute(route, 100);
    cm.setMaxTotal(100);
    client = new DefaultHttpClient(cm);
}

protected void doPost(HttpServletRequest request, HttpServletResponse response)
    throws ServletException, IOException {

    long threadId = Thread.currentThread().getId();
    log.debug("[THREAD " + threadId + "] client request received");

    // Get the input entity (SAML2)
    InputStream in = null;
    byte[] query11 = null;
    try {
        in = request.getInputStream();
        query11 = Saml2Requester.convert(in);
        log.debug("[THREAD " + threadId + "] client request SAML11:\n" + query11);
    } catch (IOException ex) {
        log.error("[THREAD " + threadId + "]\n", ex);
        return;
    } finally {
        if (in != null) {
            try {
                in.close();
            } catch (IOException ioe) {
                log.error("[THREAD " + threadId + "]\n", ioe);
            }
        }
    }

    // Proxy the request to the PDP
    HttpPost httpPost = new HttpPost(pdp_url);
    ByteArrayEntity entity = new ByteArrayEntity(query11);
    httpPost.setEntity(entity);
    HttpResponse httpResponse = null;
    try {
        httpResponse = client.execute(httpPost);
    } catch (IOException ioe) {
        log.error("[THREAD " + threadId + "]\n", ioe);
        httpPost.abort();
        return;
    }

    int sc = httpResponse.getStatusLine().getStatusCode();
    if (sc != HttpStatus.SC_OK) {
        log.error("[THREAD " + threadId + "] Bad response from PDP: " + sc);
        httpPost.abort();
        return;
    }

    // Get the response back from the PDP
    InputStream in2 = null;
    byte[] resp = null;
    try {
        HttpEntity entity2 = httpResponse.getEntity();
        in2 = entity2.getContent();
        resp = Saml2Requester.consumeStream(in2);
        EntityUtils.consumeStream(in2);
        log.debug("[THREAD " + threadId + "] client response received, SAML11: " + resp);
    } catch (IOException ex) {
        log.error("[THREAD " + threadId + "]", ex);
        httpPost.abort();
        return;
    } finally {
        if (in2 != null) {
            try {
                in2.close();
            } catch (IOException ioe) {
                log.error("[THREAD " + threadId + "]", ioe);
            }
        }
    }

    // Convert the response from SAML1.1 to SAML2 and send back
    ByteArrayInputStream respStream = null;
    byte[] resp2 = null;
    try {
        respStream = new ByteArrayInputStream(resp);
        resp2 = Saml2Responder.convert(respStream);
    } finally {
        if (respStream != null) {
            try {
                respStream.close();
            } catch (IOException ioe) {
                log.error("[THREAD " + threadId + "]", ioe);
            }
        }
    }
    log.debug("[THREAD " + threadId + "] client response SAML2: " + resp2);

    OutputStream os2 = null;
    try {
        os2 = response.getOutputStream();
        os2.write(resp2.getBytes());
        log.debug("[THREAD " + threadId + "] client response forwarded");
    } catch (IOException ex) {
        log.error("[THREAD " + threadId + "]\n", ex);
        return;
    } finally {
        if (os2 != null) {
            try {
                os2.close();
            } catch (IOException ioe) {
                log.error("[THREAD " + threadId + "]\n", ioe);
            }
        }
    }
}

public void destroy() {
    client.getConnectionManager().shutdown();
    super.destroy();
}

}

提前感谢您!

1个回答

4

HttpClient.execute()方法在被调用的服务器发送完所有HTTP头部信息之前不会返回。您的代码很好。我认为被调用的服务是真正的瓶颈。我已经创建了一个简单的概念验证代码(基于您的片段):

import java.io.IOException;

import org.apache.http.HttpHost;
import org.apache.http.HttpResponse;
import org.apache.http.HttpStatus;
import org.apache.http.StatusLine;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.conn.routing.HttpRoute;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.impl.conn.tsccm.ThreadSafeClientConnManager;

public class MyHttpClient {

    private static final String url = "http://localhost:8080/WaitServlet";

    private final DefaultHttpClient client;

    public MyHttpClient() {
        final ThreadSafeClientConnManager cm = 
                new ThreadSafeClientConnManager();
        final HttpRoute route = new HttpRoute(new HttpHost(url));
        cm.setDefaultMaxPerRoute(100);
        cm.setMaxForRoute(route, 100);
        cm.setMaxTotal(100);
        client = new DefaultHttpClient(cm);
    }

    public void doPost() {
        final HttpPost httpPost = new HttpPost(url);

        HttpResponse httpResponse;
        try {
            httpResponse = client.execute(httpPost);
        } catch (final IOException ioe) {
            ioe.printStackTrace();
            httpPost.abort();
            return;
        }

        final StatusLine statusLine = httpResponse.getStatusLine();
        System.out.println("status: " + statusLine);
        final int statusCode = statusLine.getStatusCode();
        if (statusCode != HttpStatus.SC_OK) {
            httpPost.abort();
            return;
        }
    }
}

And a test:

import java.util.concurrent.ExecutorService;
import java.util.concurrent.Executors;
import java.util.concurrent.TimeUnit;

import org.junit.Test;

public class HttpClientTest {

    @Test
    public void test2() throws Exception {
        final ExecutorService executorService = 
                Executors.newFixedThreadPool(16);

        final MyHttpClient myHttpClient = new MyHttpClient();

        for (int i = 0; i < 8; i++) {
            final Runnable runnable = new Runnable() {

                @Override
                public void run() {
                    myHttpClient.doPost();
                }
            };
            executorService.execute(runnable);
        }

        executorService.shutdown();
        executorService.awaitTermination(150, TimeUnit.SECONDS);
    }
}

最后,调用的是WaitServlet
import java.io.IOException;
import java.io.PrintWriter;

import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

public class WaitServlet extends HttpServlet {
    private static final long serialVersionUID = 1L;

    @Override
    protected void doGet(HttpServletRequest req, HttpServletResponse resp)
            throws ServletException, IOException {
        doPost(req, resp);
    }

    @Override
    protected void doPost(HttpServletRequest req, HttpServletResponse resp)
            throws ServletException, IOException {
        try {
            Thread.sleep(30 * 1000);
        } catch (InterruptedException e) {
            e.printStackTrace();
        }
        final PrintWriter writer = resp.getWriter();
        writer.println("wait end");
    }
}

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