以下是我正在运行的Windows服务框架。如果出现错误,该错误将被记录并可以在事件查看器中查看。问题在于脚本仅停止而不重新启动,即使我已将恢复设置为在第一次、第二次和后续故障时重新启动服务。目前,我的错误处理很少,因为我想在事件查看器中查看可能出现的错误,以便编写代码来相应地处理这些错误。
from win32api import CloseHandle, GetLastError, SetConsoleCtrlHandler
import os
import sys
import time
import pythoncom
import win32serviceutil
import win32service
import win32event
import servicemanager
import socket
class AppServerSvc (win32serviceutil.ServiceFramework):
_svc_name_ = "my_service_name"
_svc_display_name_ = "my service"
def __init__(self,args):
win32serviceutil.ServiceFramework.__init__(self,args)
SetConsoleCtrlHandler(lambda x: True, True)
self.hWaitStop = win32event.CreateEvent(None,0,0,None)
def SvcStop(self):
self.ReportServiceStatus(win32service.SERVICE_STOP_PENDING)
win32event.SetEvent(self.hWaitStop)
self.run = False
def SvcDoRun(self):
servicemanager.LogMsg(servicemanager.EVENTLOG_INFORMATION_TYPE,
servicemanager.PYS_SERVICE_STARTED,
(self._svc_name_,''))
self.run = True
self.main()
def main(self):
while self.run == True
pass
if __name__ == '__main__':
win32serviceutil.HandleCommandLine(AppServerSvc)
编辑:
我尝试在self.main周围使用try:except,但结果仍然相同。当服务崩溃时,它没有重新启动...请问是否有任何想法?如果无法在崩溃事件中重新启动服务,则服务并不是特别有用...最好将其作为.pyc运行
编辑:
以下是我的脚本中可能出现的错误示例...我不认为此错误消息特别有用,因为我要实现的目标是使服务重新启动,但这里是一个导致我的服务崩溃而没有重新启动的错误示例:
The instance's SvcRun() method failed
Traceback (most recent call last):
File "C:\Python27\lib\site-packages\win32\lib\win32serviceutil.py", line 806, in SvcRun
self.SvcDoRun()
File "C:\Some_Service.py", line 46, in SvcDoRun
self.main()
File "Some_Service.py", line 61, in main
ser = self.open_serial_port()
File "Some_Service.py", line 70, in open_serial_port
serial_connection.open()
File "C:\Python27\lib\site-packages\serial\serialwin32.py", line 56, in open
raise SerialException("could not open port %s: %s" % (self.portstr, ctypes.WinError()))
SerialException: could not open port COM6: [Error 1225] The remote system refused the network connection.
%2: %3