UIActivityViewController联系人分享？

Question

我正在考虑一种使用UIActivityViewController（或使用短信）从一个设备共享联系人的方法。

到目前为止，我一直在搜索，但我不知道如何使用我的应用程序在设备之间共享联系人。

有什么想法吗？

- Idan Moshe

Answer 1

经过数月的搜索，我终于找到了实现这个目标的方法。

您可以使用以下代码在UIActivityViewController中分享单个CNContact:

let contact: CNContact = /* your contact here */

let fileManager = NSFileManager.defaultManager()
let cacheDirectory = try! fileManager.URLForDirectory(NSSearchPathDirectory.CachesDirectory, inDomain: NSSearchPathDomainMask.UserDomainMask, appropriateForURL: nil, create: true)

let fileLocation = cacheDirectory.URLByAppendingPathComponent("\(CNContactFormatter().stringFromContact(contact)!).vcf")

let contactData = try! CNContactVCardSerialization.dataWithContacts([contact])
contactData.writeToFile(fileLocation.path!, atomically: true)

let activityVC = UIActivityViewController(activityItems: [fileLocation], applicationActivities: nil)
presentViewController(activityVC, animated: true, completion: nil)

此代码将联系人转换为NSData表示形式，将其保存到应用程序的缓存文件夹中，并将文件作为活动项分享。

如果您想共享多个联系人，可以通过这种方式传递多个文件。

编辑：Swift 3.0版本

let contact: CNContact = /* your contact here */

let fileManager = FileManager.default
let cacheDirectory = try! fileManager.url(for: .cachesDirectory, in: .userDomainMask, appropriateFor: nil, create: true)

let fileLocation = cacheDirectory.appendingPathComponent("\(CNContactFormatter().string(from: contact)!).vcf")

let contactData = try! CNContactVCardSerialization.data(with: [contact])
do {
    try contactData.write(to: fileLocation.asURL(), options: .atomicWrite)
} catch {
    ...
}

let activityVC = UIActivityViewController(activityItems: [fileLocation], applicationActivities: nil)
present(activityVC, animated: true, completion: nil)

- erdekhayser

Answer 2

Swift 3.0：

    let cacheDirectory = try! FileManager.default.url(for: FileManager.SearchPathDirectory.cachesDirectory, in: FileManager.SearchPathDomainMask.userDomainMask, appropriateFor: nil, create: true)

    let fileLocation = cacheDirectory.appendingPathComponent("\(CNContactFormatter().string(from: contact)!).vcf")

    let contactData = try! CNContactVCardSerialization.data(with: [contact])
    do {
        _ = try contactData.write(to: fileLocation, options: .atomic)
    } catch let error {
        print(error)
    }

- Volodymyr Smolianinov

Answer 3

您也可以使用旧的ABAddressBook框架以类似的方式轻松实现此功能（制作vCard表示形式，将其保存到文件中，共享URL）：

func AB_RecordVcardFileURL(record: ABRecord) -> NSURL? {
    let docsPath = NSSearchPathForDirectoriesInDomains(.DocumentDirectory, .UserDomainMask, true)

    guard let
        pathStr = docsPath.first as NSString?
        else {return nil}

    let name = ABRecordCopyCompositeName(record).takeRetainedValue() ?? "vcard"
    let filePath = pathStr.stringByAppendingPathComponent("\(name!).vcf")

    let fileUrl = NSURL(fileURLWithPath: filePath)

    let card = ABPersonCreateVCardRepresentationWithPeople([record]).takeRetainedValue() as NSData
    card.writeToURL(fileUrl, atomically: true)

    return fileUrl
}

然后，您只需将URL传递给活动控制器：

guard let
        fileUrl = AB_RecordVcardFileURL(record)
else {return}

let activity = UIActivityViewController(activityItems: [fileUrl], applicationActivities: nil)
presentViewController(activity, animated: true, completion: nil)

- Aviel Gross

Answer 4

版本：Swift 4.2 避免联系人没有姓名时崩溃。

let cnContact : CNContact = CNContact()
 let fileManager = FileManager.default
        do {
            let cacheDirectory = try? fileManager.url(for: .cachesDirectory, in: .userDomainMask, appropriateFor: nil, create: true)
            let fileLocation = cacheDirectory?.appendingPathComponent("\(CNContactFormatter().string(from: cnContact) ?? "Contact")).vcf")
            let contactData = try? CNContactVCardSerialization.data(with: [cnContact])
            try? contactData?.write(to: (fileLocation?.asURL())!, options: .atomicWrite)
            attachedFiles.append(fileLocation!)
        } catch let error {
            logger.info("share contact failed due to :\(error)")
        }

如果您的联系人没有姓名字段，当您尝试执行CNContactFormatter().string(from: cnContact)时，它将崩溃，因为它将返回nil。因此，为了避免崩溃，请给一些默认名称，不要强制执行。

- Abhishek Binniwale