我想在Google Maps中显示某个地址的位置。
如何使用Google Maps API获取某个地址的纬度和经度？
如何从地址中获取纬度和经度？
122
- Kandha
1
我曾经遇到同样的问题，这里是我的解决方案
https://dev59.com/QFzUa4cB1Zd3GeqP6L9s#19170557 - Bruno Pinto
10个回答
148
public GeoPoint getLocationFromAddress(String strAddress) {
Geocoder coder = new Geocoder(this);
List<Address> address;
GeoPoint p1 = null;
try {
address = coder.getFromLocationName(strAddress, 5);
if (address == null) {
return null;
}
Address location = address.get(0);
location.getLatitude();
location.getLongitude();
p1 = new GeoPoint((double) (location.getLatitude() * 1E6),
(double) (location.getLongitude() * 1E6));
return p1;
} catch (IOException e) {
e.printStackTrace();
}
return null;
}
strAddress 是一个包含地址的字符串。变量 address 保存转换后的地址。
- ud_an
15
1它抛出了“java.io.IOException服务不可用”的异常。 - Kandha
4访问该服务需要正确的权限。
<uses-permission android:name="android.permission.ACCESS_COARSE_LOCATION" />
<uses-permission android:name="android.permission.INTERNET" /> - Flo
1我已经授予了这些权限并包含了库...我可以获取地图视图...但在geocoder处抛出了IOException。 - Kandha
@Mr.Hyde，您使用的API版本是哪个？ - ud_an
6请查看下面@NayAneshGupte的答案，我认为新库中没有
GeoPoint类。 相反，可以使用LatLng。https://dev59.com/_3A65IYBdhLWcg3w5y_B#27834110 - user2968401显示剩余10条评论
93
Ud_an的解决方案使用了更新的API。
注意： LatLng类是Google Play Services的一部分。
必须注意：
<uses-permission android:name="android.permission.ACCESS_COARSE_LOCATION"/>
<uses-permission android:name="android.permission.INTERNET"/>
更新：如果您的目标SDK版本为23及以上，请确保处理位置运行时权限。
public LatLng getLocationFromAddress(Context context,String strAddress) {
Geocoder coder = new Geocoder(context);
List<Address> address;
LatLng p1 = null;
try {
// May throw an IOException
address = coder.getFromLocationName(strAddress, 5);
if (address == null) {
return null;
}
Address location = address.get(0);
p1 = new LatLng(location.getLatitude(), location.getLongitude() );
} catch (IOException ex) {
ex.printStackTrace();
}
return p1;
}
- Nayanesh Gupte
8
2谢谢，这个方法对我有用，上面的解决方案不起作用。 - Rizwan Sohaib
1在实例化Geocoder时，您应该传递上下文。例如：Geocoder coder = new Geocoder(this); 或者 new Geocoder(getApplicationContext)，而不是像答案中所述使用getActivity()。 - The_Martian
1@Quantumdroid 上面的代码是在片段中编写的。否则你是完全正确的。这是上下文。 - Nayanesh Gupte
2优美而干净的解决方案。没有一个答案提到Geocoder使用同步访问，因此强烈建议将其放入后台服务中以避免阻塞UI。 - The_Martian
1很好的解决方案。当输入无效的地址/邮编时，将调用IOException。您可以通过一个简单的
if(address.size() <1){//show a Toast}else{//put rest of code here} 来避免这个错误。 - grantespo显示剩余3条评论
53
如果您想将您的地址放在Google地图上，那么简单的方法是使用以下内容：
Intent searchAddress = new Intent(Intent.ACTION_VIEW,Uri.parse("geo:0,0?q="+address));
startActivity(searchAddress);
如果您需要从地址获取经纬度，请使用Google Place API，并按照以下步骤：
创建一个方法，返回一个带有HTTP调用响应的JSONObject，如下所示：
public static JSONObject getLocationInfo(String address) {
StringBuilder stringBuilder = new StringBuilder();
try {
address = address.replaceAll(" ","%20");
HttpPost httppost = new HttpPost("http://maps.google.com/maps/api/geocode/json?address=" + address + "&sensor=false");
HttpClient client = new DefaultHttpClient();
HttpResponse response;
stringBuilder = new StringBuilder();
response = client.execute(httppost);
HttpEntity entity = response.getEntity();
InputStream stream = entity.getContent();
int b;
while ((b = stream.read()) != -1) {
stringBuilder.append((char) b);
}
} catch (ClientProtocolException e) {
} catch (IOException e) {
}
JSONObject jsonObject = new JSONObject();
try {
jsonObject = new JSONObject(stringBuilder.toString());
} catch (JSONException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
return jsonObject;
}
现在将该 JSONObject 传递给以下的getLatLong()方法
public static boolean getLatLong(JSONObject jsonObject) {
try {
longitute = ((JSONArray)jsonObject.get("results")).getJSONObject(0)
.getJSONObject("geometry").getJSONObject("location")
.getDouble("lng");
latitude = ((JSONArray)jsonObject.get("results")).getJSONObject(0)
.getJSONObject("geometry").getJSONObject("location")
.getDouble("lat");
} catch (JSONException e) {
return false;
}
return true;
}
希望这能对你和其他人有所帮助..!! 谢谢..!!
- Nirav Dangi
2
1不幸的是，这个解决方案在某些移动运营商的移动连接中无法使用：请求总是返回 OVER_QUERY_LIMIT。这些移动运营商使用NAT过载，将同一个IP分配给多个设备... - Umberto
@UmbySlipKnot，你能详细解释一下OVER_QUERY_LIMIT吗？那是什么？谢谢。 - sfmirtalebi
7
以下代码将适用于Google API V2：
public void convertAddress() {
if (address != null && !address.isEmpty()) {
try {
List<Address> addressList = geoCoder.getFromLocationName(address, 1);
if (addressList != null && addressList.size() > 0) {
double lat = addressList.get(0).getLatitude();
double lng = addressList.get(0).getLongitude();
}
} catch (Exception e) {
e.printStackTrace();
} // end catch
} // end if
} // end convertAddress
其中，address是你想要转换为经纬度的字符串（格式为：街道地址 城市 州 邮政编码）。
- Neutrino
1
yourButton.setOnClickListener {
AppUtil.hideSoftKeyboard(this)
if (yourEdittext.text.isNotEmpty()) {
var location: LatLng? = null
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.TIRAMISU) {
val coder = Geocoder(this@WeatherMapActivity)
coder.getFromLocationName(yourEdittext.text.toString(), 5,object :Geocoder.GeocodeListener{
override fun onGeocode(addresses: MutableList<Address>) {
addresses.forEach {
//do your work android 13
Log.d("locationFRR", "onGeocode: ${it.latitude}")
Log.d("locationFRR", "onGeocode: ${it.longitude}")
location = LatLng(it.latitude, it.longitude)
}
location?.let {
Log.d("locationFRR", "onCreate: ${it.latitude}")
Log.d("locationFRR", "onCreate: ${it.longitude}")
getWeather(it.latitude.toString(), it.longitude.toString())
}
}
override fun onError(errorMessage: String?) {
super.onError(errorMessage)
Log.d("locationFRR", "onError: $errorMessage")
Toast.makeText(
this@WeatherMapActivity,
"City not found",
Toast.LENGTH_SHORT
).show()
}
})
} else {
//less than Android 13
//using Coroutine to avoid ANRs
GlobalScope.launch(Dispatchers.IO) {
location =
getLocationFromAddress(yourEdittext.text.toString())
withContext(Dispatchers.Main) {
location?.let {
Log.d("locationFRR", "onCreate: ${it.latitude}")
Log.d("locationFRR", "onCreate: ${it.longitude}")
getWeather(it.latitude.toString(), it.longitude.toString())
} ?: run {
Toast.makeText(
this@WeatherMapActivity,
"City not found",
Toast.LENGTH_SHORT
).show()
}
}
}
}
}
}
private fun getLocationFromAddress(strAddress: String): LatLng? {
val coder = Geocoder(this)
var p1: LatLng? = null
try {
val address: MutableList<Address>? = coder.getFromLocationName(strAddress, 5)
address?.let {
if (it.size > 0) {
address[0].let { add ->
p1 = LatLng(
(add.latitude),
(add.longitude)
)
}
}
Log.d("locationFRR", "getLocationFromAddress: $p1")
}
} catch (e: IOException) {
e.printStackTrace()
Log.d("locationFRR", "getLocationFromAddress: ${e.message}")
}
return p1
}
- Awais Raza
1
对于上面的Kandha问题的答案：
它抛出“java.io.IOException服务不可用”的异常，我已经授予了这些权限并包含了库...我可以获取地图视图...但在geocoder处抛出了IOException异常...
我只是在try后面添加了一个catch IOException，问题就解决了。
catch(IOException ioEx){
return null;
}
- ylag75
1
public void goToLocationFromAddress(String strAddress) {
//Create coder with Activity context - this
Geocoder coder = new Geocoder(this);
List<Address> address;
try {
//Get latLng from String
address = coder.getFromLocationName(strAddress, 5);
//check for null
if (address != null) {
//Lets take first possibility from the all possibilities.
try {
Address location = address.get(0);
LatLng latLng = new LatLng(location.getLatitude(), location.getLongitude());
//Animate and Zoon on that map location
mMap.moveCamera(CameraUpdateFactory.newLatLng(latLng));
mMap.animateCamera(CameraUpdateFactory.zoomTo(15));
} catch (IndexOutOfBoundsException er) {
Toast.makeText(this, "Location isn't available", Toast.LENGTH_SHORT).show();
}
}
} catch (IOException e) {
e.printStackTrace();
}
}
- jay patoliya
0
Geocoder coder = new Geocoder(this);
List<Address> addresses;
try {
addresses = coder.getFromLocationName(address, 5);
if (addresses == null) {
}
Address location = addresses.get(0);
double lat = location.getLatitude();
double lng = location.getLongitude();
Log.i("Lat",""+lat);
Log.i("Lng",""+lng);
LatLng latLng = new LatLng(lat,lng);
MarkerOptions markerOptions = new MarkerOptions();
markerOptions.position(latLng);
googleMap.addMarker(markerOptions);
googleMap.animateCamera(CameraUpdateFactory.newLatLngZoom(latLng,12));
} catch (IOException e) {
e.printStackTrace();
}
- Manikanta Reddy
1
1那个空值检查没有起到任何作用。 - charles-allen
0
public LatLang getLatLangFromAddress(String strAddress){
Geocoder coder = new Geocoder(this, Locale.getDefault());
List<Address> address;
try {
address = coder.getFromLocationName(strAddress,5);
if (address == null) {
return new LatLang(-10000, -10000);
}
Address location = address.get(0);
return new LatLang(location.getLatitude(), location.getLongitude());
} catch (IOException e) {
return new LatLang(-10000, -10000);
}
}
LatLang 在这种情况下是一个普通的 Java 对象类。
<uses-permission android:name="android.permission.ACCESS_COARSE_LOCATION" /> 权限不是必需的。
- Praveen
-1
我知道现在回答这个10年前的问题已经太晚了，在2021年。以下的代码是完全可用的代码。
activity_main.xml 的代码：
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:app="http://schemas.android.com/apk/res-auto"
xmlns:tools="http://schemas.android.com/tools"
android:layout_width="match_parent"
android:layout_height="match_parent"
tools:context=".MainActivity">
<TextView
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="Enter Address"
android:id="@+id/addressTV"
android:textAppearance="?android:attr/textAppearanceMedium"
android:layout_alignParentStart="true" />
<EditText
android:layout_width="fill_parent"
android:layout_height="wrap_content"
android:id="@+id/addressET"
android:layout_alignParentTop="true"
android:layout_toEndOf="@+id/addressTV"
android:singleLine="true"
android:hint="1600 Pennsylvania Ave NW Washington DC 20502" />
<Button
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="Show Lat/Long"
android:id="@+id/addressButton"
android:layout_below="@+id/addressTV"
android:layout_toEndOf="@+id/addressTV"
android:layout_marginTop="50dp" />
<TextView
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:textAppearance="?android:attr/textAppearanceLarge"
android:text=""
android:id="@+id/latLongTV"
android:layout_centerVertical="true"
android:layout_toEndOf="@+id/addressTV" />
AndroidManifest.xml 给予以下权限：
<uses-permission android:name="android.permission.ACCESS_FINE_LOCATION" />
<uses-permission android:name="android.permission.INTERNET" />
<uses-permission android:name="android.permission.ACCESS_BACKGROUND_LOCATION"/>
<uses-permission android:name="android.permission.ACCESS_COARSE_LOCATION"/>
MainActivity.java
public class MainActivity extends Activity {
Button addressButton;
TextView addressTV;
TextView latLongTV;
EditText addressET;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
addressET = findViewById(R.id.addressET);
addressTV = (TextView) findViewById(R.id.addressTV);
latLongTV = (TextView) findViewById(R.id.latLongTV);
addressButton = (Button) findViewById(R.id.addressButton);
addressButton.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View arg0) {
String address = addressET.getText().toString();
GeocodingLocation locationAddress = new GeocodingLocation();
locationAddress.getAddressFromLocation(address,
getApplicationContext(), new GeocoderHandler());
}
});
}
private class GeocoderHandler extends Handler {
@Override
public void handleMessage(Message message) {
String address;
switch (message.what) {
case 1:
Bundle bundle = message.getData();
address = bundle.getString("address");
break;
default:
address = null;
}
latLongTV.setText(address);
}
}
}
GeocodingLocation.java
public class GeocodingLocation {
public static void getAddressFromLocation(String locationAddress, Context context, Handler handler) {
Thread thread = new Thread() {
@Override
public void run() {
Geocoder geocoder = new Geocoder(context, Locale.getDefault());
String result = null;
try {
List addressList = geocoder.getFromLocationName(locationAddress,1);
if (addressList != null && addressList.size() > 0){
Address address = (Address) addressList.get(0);
StringBuilder stringBuilder = new StringBuilder();
stringBuilder.append(address.getLatitude()).append("\n");
stringBuilder.append(address.getLongitude()).append("\n");
result = stringBuilder.toString();
}
} catch (IOException e) {
e.printStackTrace();
} finally {
Message message = Message.obtain();
message.setTarget(handler);
if (result != null){
message.what = 1;
Bundle bundle = new Bundle();
result = "Address : "+locationAddress+
"\n\n\nLatitude and longitude\n"+result;
bundle.putString("address",result);
message.setData(bundle);
}
message.sendToTarget();
}
}
};
thread.start();
}
}
- Mediad
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