我有一个测试文件(只是为了链接测试),在这个文件中,我使用自己的malloc
/free
库libxmalloc.a
重载了new
/delete
运算符。但是在链接静态库时,即使我改变了test.o
和-lxmalloc
的顺序,仍然会出现“未定义引用”错误,但是其他链接该库的C程序都可以正常工作。我对这个问题感到困惑,并感谢任何线索。
错误信息:
g++ -m64 -O3 -I/usr/include/ethos -I/usr/include/nacl/x86_64 -c -o test.o test.cpp
g++ -m64 -O3 -L. -o demo test.o -lxmalloc
test.o: In function `operator new(unsigned long)':
test.cpp:(.text+0x1): undefined reference to `malloc(unsigned long)'
test.o: In function `operator delete(void*)':
test.cpp:(.text+0x11): undefined reference to `free(void*)'
test.o: In function `operator new[](unsigned long)':
test.cpp:(.text+0x21): undefined reference to `malloc(unsigned long)'
test.o: In function `operator delete[](void*)':
test.cpp:(.text+0x31): undefined reference to `free(void*)'
test.o: In function `main':
test.cpp:(.text.startup+0xc): undefined reference to `malloc(unsigned long)'
test.cpp:(.text.startup+0x19): undefined reference to `malloc(unsigned long)'
test.cpp:(.text.startup+0x24): undefined reference to `free(void*)'
test.cpp:(.text.startup+0x31): undefined reference to `free(void*)'
collect2: ld returned 1 exit status
make: *** [demo] Error 1
我的test.cpp
文件:
#include <dual/xalloc.h>
#include <dual/xmalloc.h>
void*
operator new (size_t sz)
{
return malloc(sz);
}
void
operator delete (void *ptr)
{
free(ptr);
}
void*
operator new[] (size_t sz)
{
return malloc(sz);
}
void
operator delete[] (void *ptr)
{
free(ptr);
}
int
main(void)
{
int *iP = new int;
int *aP = new int[3];
delete iP;
delete[] aP;
return 0;
}
我的Makefile
:
CFLAGS += -m64 -O3 -I/usr/include/ethos -I/usr/include/nacl/x86_64
CXXFLAGS += -m64 -O3
LIBDIR += -L.
LIBS += -lxmalloc
all: demo
demo: test.o
$(CXX) $(CXXFLAGS) $(LIBDIR) -o demo test.o $(LIBS)
test.o: test.cpp
$(CXX) $(CFLAGS) -c -o $@ $<
clean:
- rm -f *.o demo
extern "C" { #include <dual/xalloc.h> ... }
?这样可以使代码更通用。 - πάντα ῥεῖ