我需要实现一个通用的栈,但是当我尝试构建项目时,出现了一个错误,我无法解决。以下是代码:
Stack.java -> 接口
当我尝试构建该项目时,我收到了以下错误:
Stack.java -> 接口
package stack;
public interface Stack <T> {
public boolean isEmpty();
public boolean isFull();
public void push(T x) throws StackFullException;
public boolean offer(T x);
public T pop() throws StackEmptyException;
public T poll();
public T peek() throws StackEmptyException;
public T element();
}
StackArray.java -> 这是接口的实现
package stack;
public class StackArray <T extends Number> implements Stack {
static int max;
private int nr;
private T[] stack;
public StackArray(int size){
nr=0;
stack=(T[])(new Object[size]);
max=size;
}
public boolean isEmpty() {
if (nr<=0)
return true;
return false;
}
public boolean isFull() {
if (nr==max-1)
return true;
return false;
}
public void push(Object x) throws StackFullException{
if(isFull())
throw new StackFullException();
else
stack[nr++]=(T)x;
}
public boolean offer(Object x) {
if(isFull())
return false;
else
{
stack[nr++]=(T)x;
return true;
}
}
public T pop() throws StackEmptyException {
T aux=(T)(new Object());
if(isEmpty())
throw new StackEmptyException();
else
{
aux=stack[nr];
stack[nr]=null;
nr--;
return aux;
}
}
public T poll() {
T aux=(T)(new Object());
if(isEmpty())
return null;
else
{
aux=stack[nr];
stack[nr]=null;
nr--;
return aux;
}
}
public T peek() throws StackEmptyException {
if(isEmpty())
throw new StackEmptyException();
else
return stack[nr];
}
public T element() {
if(isEmpty())
return null;
else
return stack[nr];
}
}
主类如下:
package stack;
public class Main {
public static void main(String[] args) throws StackFullException, StackEmptyException {
StackArray stiva=new StackArray(10);
for(int i=1; i<10; i++)
stiva.push(i);
for(int i=1; i<10; i++)
System.out.print(stiva.pop()+" ");
}
}
当我尝试构建该项目时,我收到了以下错误:
Exception in thread "main" java.lang.ClassCastException: [Ljava.lang.Object; cannot be cast to [Ljava.lang.Number;
at stack.StackArray.<init>(StackArray.java:10)
at stack.Main.main(Main.java:5)
Java Result: 1
有人能帮助我吗?谢谢!
max
似乎没有很好的理由为空; 实际上,如果人们同时使用两个实例的堆栈,您的代码可能会相当灾难性地失败。 - Mark Peters