作为一项练习，我想创建一个生成表示瓷砖（x、y、成本、类型）的结构体的2D数组的函数。我大量使用realloc和malloc，但输出结果不是我预期的（例如代表墙的“＃”字符被省略了）。我找不到问题所在:-/。这是代码：
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int COL, ROW;
struct Tile {
int x;
int y;
int cost;
char type[10];
};
struct Tile *** generate_map(char * txt) {
int i, j, m;
struct Tile ***col = (struct Tile***) malloc(sizeof (struct Tile**));
struct Tile **row = (struct Tile**) malloc(sizeof (struct Tile*));
struct Tile *t;
i = j = m = 0;
while (txt[m] != '\0') {
if (txt[i] == '\n') {
m++;
col[j] = row;
row = (struct Tile**) malloc(sizeof (struct Tile*));
j++;
i = 0;
col = realloc(col, sizeof (struct Tile**) * (j + 1));
continue;
}
t = (struct Tile*) malloc(sizeof (struct Tile));
t->y = j;
t->x = i;
switch (txt[i]) {
case '#':
t->cost = 100;
strcpy(t->type, "wall");
break;
case '.':
t->cost = 5;
strcpy(t->type, "sand");
break;
case ',':
strcpy(t->type, "mud");
t->cost = 10;
break;
}
row[i] = t;
i++;
row = realloc(row, sizeof (struct Tile*) * (i + 1));
m++;
}
COL = j;
ROW = i;
return col;
}
int main(int argc, char** argv) {
char map[] = ".,.\n.,.\n.,.\n###\n.,.";
int i, j;
struct Tile ***k = generate_map(map);
for (i = 0; i < COL; i++) {
for (j = 0; j < ROW; j++) {
printf("x:%d y:%d, cost: %d, type: %s \n", (k[i][j])->x, (k[i][j])->y, (k[i][j])->cost, (k[i][j])->type);
}
}
return 0;
}
有什么想法是出了问题吗？