如何使用jq将嵌套对象转换为扁平化对象?

4

我需要使用 jq 将此输入转换为非嵌套对象。在 Python 中,我可以按照以下方式正确地进行转换。

output = {(k1 + '-' + k2): v2 for k1, v1 in input.iteritems() for k2, v2 in v1.iteritems()}

但是我无法弄清楚如何在jq中实现这一点。操作嵌套对象的文档非常简陋。

{
    "group1-permission": {
        "address": "test1",
        "others": "test2",
        "packet-capture": "test3",
        "policy": "test4",
        "schedule": "test5",
        "service": "test6"
    },
    "group2-permission": {
        "config": "none",
        "data-access": "none",
        "report-access": "none",
        "threat-weight": "none"
    },
    "group3-permission": {
        "antivirus": "none",
        "application-control": "none",
        "casi": "none",
        "data-loss-prevention": "none",
        "dnsfilter": "none",
        "icap": "none",
        "ips": "none",
        "spamfilter": "none",
        "voip": "none",
        "waf": "none",
        "webfilter": "none"
    }
}

输出应该是这样的:
{
    "group1-permission-address": "test1",
    "group1-permission-others": "test2",
    "group1-permission-packet-capture": "test3",
    "group1-permission-policy": "test4",
    "group1-permission-schedule": "test5",
    "group1-permission-service": "test6",
    "group2-permission-config": "none",
    "group2-permission-data-access": "none",
    "group2-permission-report-access": "none",
    "group2-permission-threat-weight": "none",
    "group3-permission-antivirus": "none",
    "group3-permission-application-control": "none",
    "group3-permission-casi": "none",
    "group3-permission-data-loss-prevention": "none",
    "group3-permission-dnsfilter": "none",
    "group3-permission-icap": "none",
    "group3-permission-ips": "none",
    "group3-permission-spamfilter": "none",
    "group3-permission-voip": "none",
    "group3-permission-waf": "none",
    "group3-permission-webfilter": "none"
}
1个回答

6

在我看来,这份文档非常出色,但如果您对map有一定的了解并且对管道和过滤器有一定的熟悉度会更有帮助。无论如何,这里是一个以map为导向的解决方案:

to_entries
| map( .key as $key
       | .value
       | to_entries
       | map ( { ($key + "-" + .key): .value } ) | add ) | add

这里有另一种方法,适用于任意深度嵌套的JSON对象和数组:
[paths(scalars) as $path | { ($path|join("-")): getpath($path) }] | add

当然,这里有一个警告:如果使用“-”作为连接字符导致路径冲突,则可能会丢失一些数据。


谢谢您。我已经头痛了很久,这个方法非常有效。 - mhcomputing

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