如何正确地序列化和反序列化CSV文件?

3

我一直在尝试将一个对象序列化为CSV字符串,但是这个对象包含一个列表,并且@JsonUnwrapped无法处理列表对象。

期望的样例输出

color,part.name\n
red,gearbox\n
red,door\n
red,bumper

实际输出:

com.fasterxml.jackson.core.JsonGenerationException: Unrecognized column 'name':

这是我的代码:(大部分是两个POJO)

import com.fasterxml.jackson.annotation.JsonAutoDetect;
import com.fasterxml.jackson.annotation.JsonFormat;
import com.fasterxml.jackson.annotation.JsonInclude;
import com.fasterxml.jackson.annotation.JsonProperty;
import com.fasterxml.jackson.annotation.JsonPropertyOrder;
import com.fasterxml.jackson.annotation.JsonRootName;
import com.fasterxml.jackson.dataformat.csv.CsvMapper;
import com.fasterxml.jackson.dataformat.csv.CsvSchema;
import com.fasterxml.jackson.dataformat.xml.annotation.JacksonXmlElementWrapper;
import java.io.IOException;
import static java.util.Arrays.asList;
import java.util.List;
import java.util.logging.Level;
import java.util.logging.Logger;

public class NestedWrapping {

@JsonRootName("Car")
@JsonInclude(JsonInclude.Include.NON_DEFAULT)
@JsonAutoDetect(fieldVisibility = JsonAutoDetect.Visibility.ANY, getterVisibility = JsonAutoDetect.Visibility.NONE, setterVisibility = JsonAutoDetect.Visibility.NONE)
@JsonPropertyOrder({"color"})
public static class Car {

    @JsonProperty("color")
    private String color;

    @JsonFormat(shape = JsonFormat.Shape.STRING)
    @JacksonXmlElementWrapper(useWrapping = false)
    private List<Part> parts;

    public String getColor() {
        return color;
    }

    public void setColor(String color) {
        this.color = color;
    }

    public List<Part> getParts() {
        return parts;
    }

    public void setParts(List<Part> parts) {
        this.parts = parts;
    }

}

@JsonInclude(JsonInclude.Include.NON_DEFAULT)
@JsonAutoDetect(fieldVisibility = JsonAutoDetect.Visibility.ANY, getterVisibility = JsonAutoDetect.Visibility.NONE, setterVisibility = JsonAutoDetect.Visibility.NONE)
@JsonPropertyOrder({
    "name"
})
public static class Part {

    @JsonProperty("name")
    private String name;

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

}

public static void main(String args[]) {
    try {
        Car car = new Car();
        car.setColor("red");
        Part part1 = new Part();
        part1.setName("geabox");
        Part part2 = new Part();
        part2.setName("door");
        Part part3 = new Part();
        part3.setName("bumper");
        car.setParts(asList(part1, part2, part3));
        System.out.println("serialized: " + serialize(car, Car.class, true));
    } catch (IOException ex) {
        Logger.getLogger(NestedWrapping.class.getName()).log(Level.SEVERE, null, ex);
    }
}

public static final synchronized String serialize(final Object object, final Class type, final Boolean withHeaders) throws IOException {
    CsvMapper csvMapper = new CsvMapper();
    CsvSchema csvSchema;
    if (withHeaders) {
        csvSchema = csvMapper.schemaFor(type).withHeader();
    } else {
        csvSchema = csvMapper.schemaFor(type).withoutHeader();
    }
    return csvMapper.writer(csvSchema).writeValueAsString(object);
}

}

无论我尝试什么,都似乎不起作用。我已经阅读了关于这个主题的stackoverflow和github上的每篇帖子(链接) ,但我找不到一个可行的解决方案。

对于任何我因无聊而留下的毫无意义的注释,我表示抱歉。如果您以代码回答,请随意删除它们。


你使用CSV而不是JSON有什么原因吗?据我所知,一个汽车中有许多零件,我认为CSV并不是最好的格式来表示它。 - OneCricketeer
我也在使用XML和JSON,但我需要能够用这三种格式来表示它。其他两种已经可以正常工作了。 - Hooli
@SotiriosDelimanolis:完成。基本上与数据库JOIN的概念相同。 - Hooli
@StaxMan:有什么想法吗? - Hooli
1
我不明白你如何从你提供的内容中得到3行,因为你只序列化了一个Car对象。每一行都是一个对象。因此,你的数据可能看起来像red,“gearbox,door,bumper”,但我不确定Jackson CSV如何表示列表。 - OneCricketeer
2个回答

6

从错误中可以猜测,与Car的模式有关,该模式从Car上的@JsonPropertyOrder提取{"color"}列,但未包括值"name"

您可能想要添加"parts",但是会遇到同样的错误,因为"name"不是该模式的一部分。

对代码进行了一些更改后,我能够序列化和反序列化Car对象。

Part

在这里,它需要一个带有单个字符串值的构造函数,因此请添加它。

@JsonPropertyOrder({"name"})
public static class Part {
    @JsonProperty("name")
    private String name;

    public Part() {
        this("");
    }

    public Part(String partJSON) {
        // TODO: Unserialize the parameter... it is a serialized Part string... 
        this.name = partJSON;
    }

汽车

在这里,您需要实现一种将 List<Part> 手动转换为 CSV 可读格式的方法。

这样的方法看起来像这样:

@JsonGetter("parts")
public String getPartString() {
    String separator = ";";
    StringBuilder sb = new StringBuilder();

    Iterator<Part> iter = this.parts.iterator();
    while (iter.hasNext()) {
        Part p = iter.next();
        sb.append(p.getName());

        if (iter.hasNext())
            sb.append(separator);
    }

    return sb.toString();
} 

另外,不要忘记修复类顶部的架构。
@JsonPropertyOrder({"color", "parts"})
public static class Car {

    @JsonProperty("color")
    private String color;
    @JsonProperty("parts")
    private List<Part> parts;

    public Car() {
        this.parts = new ArrayList<>();
    }

序列化

您可以将serialize方法更改为使用类的类型作为泛型类型参数,而不是显式的Class,如下所示。

public static final synchronized <T> String serialize(final T object, final Boolean withHeaders) throws IOException {
    CsvMapper csvMapper = new CsvMapper();
    CsvSchema csvSchema = csvMapper.schemaFor(object.getClass());

    if (withHeaders) {
        csvSchema = csvSchema.withHeader();
    } else {
        csvSchema = csvSchema.withoutHeader();
    }

    return csvMapper.writer(csvSchema).writeValueAsString(object);
}

主函数 - 编写者

现在,如果你序列化一个Car,你应该会看到

color,parts
red,gearbox;door;bumper

主函数 - 读取器

读取CSV字符串并循环遍历Car.getParts()

Car car = mapper.readerFor(Car.class).with(csvSchema).readValue(csv);

for (Part p : car.getParts()) {
    System.out.println(p.getName());
}

gearbox
door
bumper

很抱歉回复晚了。感谢您澄清了所有事情。我已经贴出完整的解决方案,供需要工作的CSV序列化/反序列化解决方案的人使用。 - Hooli
欢迎。看起来你没有采纳我的关于序列化方法的评论。 - OneCricketeer

1
完整可用的CSV序列化和反序列化解决方案:
import com.fasterxml.jackson.annotation.JsonGetter;
import com.fasterxml.jackson.annotation.JsonProperty;
import com.fasterxml.jackson.annotation.JsonPropertyOrder;
import com.fasterxml.jackson.databind.MappingIterator;
import com.fasterxml.jackson.dataformat.csv.CsvMapper;
import com.fasterxml.jackson.dataformat.csv.CsvSchema;
import java.io.IOException;
import java.util.ArrayList;
import static java.util.Arrays.asList;
import java.util.Iterator;
import java.util.List;
import java.util.logging.Level;
import java.util.logging.Logger;

public class NestedWrapping {

    @JsonPropertyOrder({"color", "parts"})
    public static class Car {

        @JsonProperty("color")
        private String color;

        @JsonProperty("parts")
        private List<Part> parts;

        public String getColor() {
            return color;
        }

        public void setColor(String color) {
            this.color = color;
        }

        public List<Part> getParts() {
            return parts;
        }

        public void setParts(List<Part> parts) {
            this.parts = parts;
        }

        public Car() {
            this.parts = new ArrayList<>();
        }

        @JsonGetter("parts")
        public String getPartString() {
            String separator = ";";
            StringBuilder sb = new StringBuilder();

            Iterator<Part> iter = this.parts.iterator();
            while (iter.hasNext()) {
                Part p = iter.next();
                sb.append(p.getName());

                if (iter.hasNext()) {
                    sb.append(separator);
                }
            }

            return sb.toString();
        }

        @Override
        public String toString() {
            return "Car{" + "color=" + color + ", parts=" + parts + '}';
        }

    }

    @JsonPropertyOrder({
        "name"
    })
    public static class Part {

        @JsonProperty("name")
        private String name;

        public Part() {
        }

        public Part(String name) {
            this.name = name;
        }

        public String getName() {
            return name;
        }

        public void setName(String name) {
            this.name = name;
        }

        @Override
        public String toString() {
            return "Part{" + "name=" + name + '}';
        }

    }

    public static void main(String args[]) {
        try {
            Car car = new Car();
            car.setColor("red");
            Part part1 = new Part();
            part1.setName("geabox");
            Part part2 = new Part();
            part2.setName("door");
            Part part3 = new Part();
            part3.setName("bumper");
            car.setParts(asList(part1, part2, part3));
            String serialized = serialize(car, Car.class, true);
            System.out.println("serialized: " + serialized);
            List<Car> deserializedCars = (List) deserialize(serialized, Car.class, true);
            for (Car deserializedCar : deserializedCars) {
                System.out.println("deserialized: " + deserializedCar.toString());
            }
        } catch (IOException ex) {
            Logger.getLogger(NestedWrapping.class.getName()).log(Level.SEVERE, null, ex);
        }
    }

    public static final synchronized String serialize(final Object object, final Class type, final Boolean withHeaders) throws IOException {
        CsvMapper csvMapper = new CsvMapper();
        CsvSchema csvSchema;
        if (withHeaders) {
            csvSchema = csvMapper.schemaFor(type).withHeader();
        } else {
            csvSchema = csvMapper.schemaFor(type).withoutHeader();
        }
        return csvMapper.writer(csvSchema).writeValueAsString(object);
    }

    public static final synchronized List<Object> deserialize(final String csv, final Class type, final Boolean hasHeaders) throws IOException {
        CsvMapper csvMapper = new CsvMapper();
        CsvSchema csvSchema;
        if (hasHeaders) {
            csvSchema = csvMapper.schemaFor(type).withHeader();
        } else {
            csvSchema = csvMapper.schemaFor(type).withoutHeader();
        }
        MappingIterator<Object> mappingIterator = csvMapper.readerFor(type).with(csvSchema).readValues(csv);
        List<Object> objects = new ArrayList<>();
        while (mappingIterator.hasNext()) {
            objects.add(mappingIterator.next());
        }
        return objects;
    }

}

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