有没有一种方法可以获取当前抛出的异常(如果存在)?
我想要减少代码量并对类似以下任务应用一些重用:
Exception thrownException = null;
try {
// some code with 3rd party classes, which can throw unexpected exceptions
}
catch( Exception exc ) {
thrownException = exc;
LogException( exc );
}
finally {
if ( null == thrownException ) {
// some code
}
else {
// some code
}
}
将其替换为以下代码:
using( ExceptionHelper.LogException() ) {
// some code with 3rd party classes, which can throw unexpected exceptions
}
using( new ExceptionHelper { ExceptionAction = ()=> /*some cleaning code*/ } ) {
// some code with 3rd party classes, which can throw unexpected exceptions
}
public class ExceptiohHelper : IDisposable {
public static ExceptionHelper LogException() {
return new ExceptionHelper();
}
public Action SuccessfulAction {get; set;}
public Action ExceptionAction {get; set;}
public void Dispose() {
Action action;
Exception thrownException = TheMethodIDontKnow();
if ( null != thrownException ) {
LogException( thrownException );
action = this.ExceptionAction;
}
else {
action = this.SuccessfulAction;
}
if ( null != action ) {
action();
}
}
}
这种情况可能吗?
谢谢