我正在尝试理解应用程序中各个线程消耗CPU时间的数学原理。下面的.time
命令告诉我,我的进程运行了约7分钟,这是我理解中该进程总共消耗的CPU时间。基于此,各个线程消耗的时间应该加起来也是7分钟,但实际上超过了7分钟。
0:140> .time
Debug session time: Fri May 8 15:05:16.000 2015 (UTC - 4:00)
System Uptime: 22 days 17:00:27.560
Process Uptime: 0 days 0:06:45.000
Kernel time: 0 days 0:00:23.000
User time: 0 days 0:26:24.000
0:140> !runaway
User Mode Time
Thread Time
8:39f4 0 days 0:01:46.236
126:1184 0 days 0:01:45.394
136:b9c 0 days 0:01:42.851
117:37c8 0 days 0:01:42.009
132:fb8 0 days 0:01:38.046
135:4a94 0 days 0:01:33.834
131:3dd0 0 days 0:01:31.525
134:5850 0 days 0:01:30.964
133:239c 0 days 0:01:30.839
139:34b8 0 days 0:01:17.438
141:381c 0 days 0:01:02.197
127:221c 0 days 0:01:00.528
140:5514 0 days 0:01:00.263
142:17b8 0 days 0:00:58.172
143:46ac 0 days 0:00:57.377
146:43d4 0 days 0:00:31.933
0:2580 0 days 0:00:31.715
4:3c98 0 days 0:00:24.663
3:2ab4 0 days 0:00:24.117
5:35c0 0 days 0:00:23.353
2:3084 0 days 0:00:22.916
148:596c 0 days 0:00:22.729
119:5b58 0 days 0:00:04.586
19:56a4 0 days 0:00:04.336
86:4bfc 0 days 0:00:03.712
130:51f0 0 days 0:00:03.697
106:20cc 0 days 0:00:03.369
118:27f0 0 days 0:00:03.229
49:56a0 0 days 0:00:03.213
121:55f8 0 days 0:00:03.198
120:1b58 0 days 0:00:03.073
30:49c0 0 days 0:00:02.542
28:4b04 0 days 0:00:02.496
26:1410 0 days 0:00:02.449
52:3750 0 days 0:00:02.418
114:140 0 days 0:00:02.386
27:4c5c 0 days 0:00:02.277
21:2748 0 days 0:00:02.277
36:26dc 0 days 0:00:02.262
70:5a78 0 days 0:00:02.246
68:232c 0 days 0:00:02.230
62:37d8 0 days 0:00:02.230
93:5b18 0 days 0:00:02.215
92:3ea8 0 days 0:00:02.199
82:106c 0 days 0:00:02.199
76:5010 0 days 0:00:02.199
125:1480 0 days 0:00:02.168
107:4c44 0 days 0:00:02.106
90:59d4 0 days 0:00:02.106
24:2128 0 days 0:00:02.074
85:34a4 0 days 0:00:01.872
17:22cc 0 days 0:00:01.825