Python Requests如何传递IP地址而非URL链接

Question

我想在Python中的请求中传递IP地址而不是URL链接。

例如：传递IP地址而不是URL链接：

requests.get(url="172.217.168.228")

所以基本上是传递IP地址而不是URL链接。我该如何实现呢？

我猜我应该传递相关端口，但是怎么做呢？

我试了几件事情，但我得到了一堆错误，比如：

requests.exceptions.MissingSchema: Invalid URL '172.217.168.228': No schema supplied. Perhaps you meant http://172.217.168.228?

或者

 File "/Users/ali/Desktop/cdn-detection/venv/lib/python3.9/site-packages/requests/adapters.py", line 514, in send
    raise SSLError(e, request=request)
requests.exceptions.SSLError: HTTPSConnectionPool(host='172.217.168.228', port=443): Max retries exceeded with url: / (Caused by SSLError(SSLCertVerificationError(1, '[SSL: CERTIFICATE_VERIFY_FAILED] certificate verify failed: self signed certificate (_ssl.c:1129)')))

或者

File "/Users/ali/Desktop/cdn-detection/venv/lib/python3.9/site-packages/requests/adapters.py", line 516, in send
    raise ConnectionError(e, request=request)
requests.exceptions.ConnectionError: HTTPSConnectionPool(host='172.217.168.228.com', port=443): Max retries exceeded with url: / (Caused by NewConnectionError('<urllib3.connection.HTTPSConnection object at 0x7f9be196a0a0>: Failed to establish a new connection: [Errno 8] nodename nor servname provided, or not known'))

- Ali

---

你可以使用IP地址代替主机名，但仍需要一个方案（http或https），这就是为什么会出现“MissingSchema”异常的原因。使用"https://172.217.168.228"。 - DisappointedByUnaccountableMod

Answer 1

您需要告诉requests模块伪造Host头信息，并将URL中的主机名替换为IP地址：

requests.get("http://172.217.168.228", headers={"Host": "www.google.com"})

for more info, you can see this link

- Ali Ent