在PHP的curl中指定multipart/form-data每个部分的Content-Type

Question

我应该如何指定multipart/form-data请求中特定部分的内容类型？图片的内容类型被发送为application/octet-stream，但服务器希望它是image/jpeg。这导致服务器拒绝我的请求。

$data["file"] = "@/image.jpg";
$data["title"] = "The title";
$data["description"] = "The description";

//make the POST request
$curl = curl_init();
curl_setopt($curl, CURLOPT_URL,$url);
curl_setopt($curl, CURLOPT_VERBOSE, 1);
curl_setopt($curl, CURLOPT_RETURNTRANSFER, true);
curl_setopt($curl, CURLOPT_HTTPHEADER, $header);
curl_setopt($curl, CURLOPT_POSTFIELDS, $data);
$result = curl_exec($curl);

这是请求的相关部分：

Content-Type: multipart/form-data; boundary=----------------------------fc57f743c490

------------------------------fc57f743c490
Content-Disposition: form-data; name="file"; filename="NASA-23.jpg"
Content-Type: application/octet-stream

I want it to be:

Content-Type: multipart/form-data; boundary=----------------------------fc57f743c490

------------------------------fc57f743c490
Content-Disposition: form-data; name="file"; filename="NASA-23.jpg"
Content-Type: image/jpeg

- devin_s

Answer 1

你可以这样做：

$data["file"] = "@/image.jpg;type=image/jpeg";

//make the POST request
$curl = curl_init();
curl_setopt($curl, CURLOPT_URL,$url);
curl_setopt($curl, CURLOPT_VERBOSE, 1);
curl_setopt($curl, CURLOPT_RETURNTRANSFER, true);
curl_setopt($curl, CURLOPT_HTTPHEADER, $header);
curl_setopt($curl, CURLOPT_POSTFIELDS, $data);
$result = curl_exec($curl);

- ZZ Coder

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示例中未定义 $header。这是必须的吗？ - m3nda