动态将对象值添加到<p>标签内的div中

Question

动态将对象值添加到<p>标签内的div中

3

点击一个按钮后，我想在现有的 div 中添加一个包含对象属性名称值的 p 标签。

  var foodLoads = {
    orange: 6.7,
    apple: 5.6,
    banana: 12.7,
    grapes: 16.3,
    peach: 2.7,
    pear: 6.5,
    mango: 16.1,
    blueberries: 9.3,
    grapefruit: 1.7,
    strawberry: 3.5,
    tangerine: 3.1,
    watermelon: 8,
    duck: 0,
    beef: 0,
    chicken: 0,
    ham: 0,
    turkey: 0,
    elk: 0,
    pork: 0,
    fish: 0,
    eggs: 0,
    lamb: 0,
    applejuice: 11.8,
    cranberryjuice: 23.3,
    orangejuice: 14.4,
    carrotjuice: 8.6,
    lemonade: 24.3,
    hotchocolatemix: 10.2,
    tomatojuice: 3.5,
    chocolatemilk: 13.3,
    almondmilk: 0.02,
    soymilk: 4,
    wholewheatbread: 6.1,
    whitebread: 10.7,
    bagel: 30,
    waffle: 13.8,
    pancake: 5.3,
    croissant: 12.2,
    muffin: 28.8,
    englishmuffin: 21.3,
    doughnut: 15.2,
    oatmeal: 12.6,
    quinoa: 20.4,
    wholegrainbread: 7.1 
  }

当用户勾选复选框时（在点击按钮之前），动态创建div。

  $('input').on('ifChecked', function(event) {       
    var liText = $(this).parent().parent().text();
    var wrappedUp = $('<div class="active"><li>' + liText + '</li><select class="serving-size"><option value="1">1</option><option value="2">2</option><option value="3">3</option><option value="4">4</option></select></div>');
    $('.food-list').append(wrappedUp);
    $(wrappedUp).addClass('' + liText + '');        
})

这是我所说的div的一个示例。

<ul class="food-list">

    <div class="active Mango">
                 <li>Mango</li>
          <select class="serving-size"><option value="1">1</option><optionvalue="2">2</option><option value="3">3</option><option value="4">4</option>
          </select>
    </div>
</ul>

所以，基本上，当点击一个按钮时，我希望能够使用类（即Mango）将其与foodLoads对象中同名（即mango）的属性匹配，将该属性的值放入p标签中，并添加到具有相同类（Mango）的div中。

这是我试图使用的jQuery。由于我对jQuery很陌生，所以我确定语法都弄错了。

  $('.submit-items').click(function() {
    $.each( foodLoads, function( key, value ) {
      if ($('.active:contains(' + key + ')')) {
        $(this).append('<p>' + key + '</li>');
      }
})

     })

有任何想法？提前谢谢 :)

- Edson

1个回答

网页内容由stack overflow 提供, 点击上面的

可以查看英文原文，
原文链接

- BenG · Accepted Answer

这里有一个更简单的方法。

找到具有active类的li的文本。
查找其值。
添加p。

例如：

$('.submit-items').click(function() {
   var type = $('.food-list .active li').text();
   var value = foodLoads[type.toLowerCase()];
   $('.' + type).append('<p>' + value + '</p>');
});

演示

var foodLoads = {
  orange: 6.7,
  apple: 5.6,
  banana: 12.7,
  grapes: 16.3,
  peach: 2.7,
  pear: 6.5,
  mango: 16.1,
  blueberries: 9.3,
  grapefruit: 1.7,
  strawberry: 3.5,
  tangerine: 3.1,
  watermelon: 8,
  duck: 0,
  beef: 0,
  chicken: 0,
  ham: 0,
  turkey: 0,
  elk: 0,
  pork: 0,
  fish: 0,
  eggs: 0,
  lamb: 0,
  applejuice: 11.8,
  cranberryjuice: 23.3,
  orangejuice: 14.4,
  carrotjuice: 8.6,
  lemonade: 24.3,
  hotchocolatemix: 10.2,
  tomatojuice: 3.5,
  chocolatemilk: 13.3,
  almondmilk: 0.02,
  soymilk: 4,
  wholewheatbread: 6.1,
  whitebread: 10.7,
  bagel: 30,
  waffle: 13.8,
  pancake: 5.3,
  croissant: 12.2,
  muffin: 28.8,
  englishmuffin: 21.3,
  doughnut: 15.2,
  oatmeal: 12.6,
  quinoa: 20.4,
  wholegrainbread: 7.1
};

$('.submit-items').click(function() {
  var type = $('.food-list .active li').text();
  var value = foodLoads[type.toLowerCase()];
  $('.' + type).append('<p>' + value + '</p>');
});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<ul class="food-list">
  <div class="active Mango">
    <li>Mango</li>
    <select class="serving-size">
      <option value="1">1</option>
      <option value="2">2</option>
      <option value="3">3</option>
      <option value="4">4</option>
    </select>
  </div>
</ul>

<button class="submit-items">submit</button>