Ruby警告：条件中的字符串字面量

Question

在第七行，我收到了“条件中的字符串文字”警告。这个警告是什么意思，我该如何解决它？

   print 'Continue to use calculator?   Y or N'
   userAgree = gets.chomp
   if userAgree == 'Y' or 'y'
        userAgree = true
   else
        userAgree = false
   end

- Russian Street Bear

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user_agree = (gets.chomp.upcase == 'Y') - steenslag

Answer 1

修改

if userAgree == 'Y' or 'y'

"要"

if userAgree == 'Y' or userAgree == 'y'

或者，依我的看法更为简洁明了：

if userAgree.upcase() == 'Y'

- Darshan Rivka Whittle

Answer 2

您的if条件无效。这个有效。

print 'Continue to use calculator?   Y or N'
userAgree = gets.chomp
if userAgree == 'Y' or userAgree == 'y'
  userAgree = true
else
  userAgree = false
end

- Damien MATHIEU

Answer 3

你可以这样做：

    puts 'Continue to use calculator?   Y or N'
    userAgree = gets.chomp
    userAgree.to_s.upcase!

    def Check (ans)

    if ["Y","N"].include?(ans)
        puts"true"
    else
        puts "false"
    end

end

Check userAgree

- ahmed hamdy

Answer 4

为什么不呢？

if userAgree == ('Y' or 'y')

对我来说，这种语法更具表现力。

- Theta

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因为这与使用 if userAgree == 'Y' 相同。表达式 'Y' or 'y' 总是会被评估为 'Y'！ - omninonsense