当我在我的 pom.xml
中添加以下代码以支持 Querydsl 时
<plugin>
<groupId>com.mysema.maven</groupId>
<artifactId>apt-maven-plugin</artifactId>
<version>1.0.6</version>
<executions>
<execution>
<goals>
<goal>process</goal>
</goals>
<configuration>
<outputDirectory>target/generated-sources/java</outputDirectory>
<processor>com.mysema.query.apt.jpa.JPAAnnotationProcessor</processor>
</configuration>
</execution>
</executions>
</plugin>
在使用Eclipse构建时,我遇到了这个错误。我认为它与类路径和JDK jars有关。
You need to run build with JDK or have tools.jar on the classpath.
If this occures during eclipse build make sure you run eclipse under JDK as well
(com.mysema.maven:apt-maven-plugin:1.0.6:process:default:generate-sources)
.classpath :
<?xml version="1.0" encoding="UTF-8"?>
<classpath>
<classpathentry kind="src" output="target/classes" path="src">
<attributes>
<attribute name="optional" value="true"/>
<attribute name="maven.pomderived" value="true"/>
</attributes>
</classpathentry>
<classpathentry kind="con" path="org.eclipse.jst.server.core.container/org.eclipse.jst.server.tomcat.runtimeTarget/Apache Tomcat v8.0">
<attributes>
<attribute name="owner.project.facets" value="jst.web"/>
</attributes>
</classpathentry>
<classpathentry kind="con" path="org.eclipse.jdt.launching.JRE_CONTAINER/org.eclipse.jdt.internal.debug.ui.launcher.StandardVMType/JavaSE-1.7">
<attributes>
<attribute name="maven.pomderived" value="true"/>
</attributes>
</classpathentry>
<classpathentry kind="con" path="org.eclipse.m2e.MAVEN2_CLASSPATH_CONTAINER">
<attributes>
<attribute name="maven.pomderived" value="true"/>
<attribute name="org.eclipse.jst.component.dependency" value="/WEB-INF/lib"/>
</attributes>
</classpathentry>
<classpathentry kind="output" path="target/classes"/>
</classpath>
额外信息:
我的Maven安装
JAVA_HOME:C:\Program Files\Java\jdk1.7.0_45
PATH: %JAVA_HOME%\bin;
Windows > Preference > Maven > Installations
,那里有哪些条目?另外,您的.classpath
是什么样子的? - Donovan Muller