我正在尝试按照mtl库的思路实现MaybeT。以下是无法编译的解决方案:
{-# LANGUAGE FlexibleInstances, MultiParamTypeClasses, UndecidableInstances #-}
import Control.Monad
import Control.Monad.Trans
import Control.Monad.State
newtype MaybeT m a = MaybeT { runMaybeT :: m (Maybe a) }
instance (Monad m) => Monad (MaybeT m) where
x >>= f = MaybeT $ runMaybeT x >>= maybe (return Nothing) (runMaybeT . f)
return a = MaybeT $ return (Just a)
fail _ = MaybeT $ return Nothing
instance MonadTrans MaybeT where
lift m = MaybeT (liftM Just m)
instance (MonadIO m) => MonadIO (MaybeT m) where
liftIO m = lift (liftIO m)
instance (MonadState s m) => MonadState s (MaybeT m) where
get = lift get
put = lift . put
...
我遇到了以下错误:
无法推断出(来自上下文(Monad m)的实例声明的超类)(MaybeT m的应用程序)
如果我实现以下内容,则可以编译:
instance (Monad m) => Applicative (MaybeT m) where
pure = return
(<*>) = ap
instance (Monad m) => Functor (MaybeT m) where
fmap = liftM
GHC 能为我做到这一点吗?