Android多点触控绘图应用未完成功能

4

我正在开发一款绘图应用程序,onTouchEvents是标准的,我想添加Undo()函数以删除上次绘制的路径。

声明:

int thelastLineId=0;
private Bitmap bitmap; // drawing area for display or saving
private Canvas bitmapCanvas; // used to draw on bitmap
private Paint paintScreen; // use to draw bitmap onto screen
private Paint paintLine; // used to draw lines onto bitmap
private HashMap<Integer, Path> pathMap; // current Paths being drawn
private HashMap<Integer, Path> reservedpathMap; // for saving the paths being undone
private HashMap<Integer, Point> previousPointMap; // current Points

构造函数:

pathMap = new HashMap<Integer, Path>();
reservedpathMap = new HashMap <Integer,Path>(); // for storing path being undone
previousPointMap = new HashMap<Integer, Point>();

onDraw:

   @Override
   protected void onDraw(Canvas canvas) 
   {
       canvas.drawBitmap(bitmap, 0, 0, paintScreen);
       // for each path currently being drawn
       for (Integer key : pathMap.keySet()) 
            canvas.drawPath(pathMap.get(key), paintLine); // draw line     
   } 

onTouchEvent:

   @Override
   public boolean onTouchEvent(MotionEvent event) 
   {                  
      int action = event.getActionMasked(); // event type 
      int actionIndex = event.getActionIndex(); // pointer (i.e., finger)

      if (action == MotionEvent.ACTION_DOWN) 
      {       
          touchStarted(event.getX(actionIndex), event.getY(actionIndex), event.getPointerId(actionIndex));
      } 
      else if (action == MotionEvent.ACTION_UP) 
      {
          touchEnded(event.getPointerId(actionIndex));
      } 
      else 
      {
         touchMoved(event); 
      } 

      invalidate();
      return true; 
   } 

touchStarted:

   private void touchStarted(float x, float y, int lineID) // lineID represents how many fingers, 1 finger 1 line
   {      
      Path path; // used to store the path for the given touch id
      Point point; // used to store the last point in path

      // if there is already a path for lineID
      if (pathMap.containsKey(lineID)) 
      {
         path = pathMap.get(lineID); // get the Path
         path.reset(); // reset the Path because a new touch has started
         point = previousPointMap.get(lineID); // get Path's last point
      } 
      else 
      {
         path = new Path(); // create a new Path
         pathMap.put(lineID, path); // add the Path to Map
         point = new Point(); // create a new Point
         previousPointMap.put(lineID, point); // add the Point to the Map
      } 

      path.moveTo(x, y);
      point.x = (int) x;  
      point.y = (int) y;  
   } 

touchMoved:

   private void touchMoved(MotionEvent event) 
   {
      // for each of the pointers in the given MotionEvent
      for (int i = 0; i < event.getPointerCount(); i++) 
      {
         // get the pointer ID and pointer index
         int pointerID = event.getPointerId(i);
         int pointerIndex = event.findPointerIndex(pointerID);

         // if there is a path associated with the pointer
         if (pathMap.containsKey(pointerID)) 
         {
            float newX = event.getX(pointerIndex);
            float newY = event.getY(pointerIndex);

            // get the Path and previous Point associated with this pointer
            Path path = pathMap.get(pointerID);
            Point point = previousPointMap.get(pointerID);

            float deltaX = Math.abs(newX - point.x);
            float deltaY = Math.abs(newY - point.y);
            if (deltaX >= TOUCH_TOLERANCE || deltaY >= TOUCH_TOLERANCE) 
            {
               path.quadTo(point.x, point.y, ((newX + point.x)/2),((newY + point.y)/2));

               point.x = (int) newX ; 
               point.y = (int) newY ; 
         } 
      }      
   } 

touchEnded:

   private void touchEnded(int lineID)
   {
      Path path = pathMap.get(lineID); // get the corresponding Path
      bitmapCanvas.drawPath(path, paintLine); 
      path.reset();           
   }

撤销:

   public void undo()
   {
       Toast.makeText(getContext(), "undo button pressed" + thelastLineId, Toast.LENGTH_SHORT).show();

       Path path = pathMap.get(thelastLineId); 
       reservedpathMap.put(thelastLineId, path); // add the Path to reservedpathMap for later redo
       pathMap.remove(thelastLineId);   

       invalidate();          
   } 

问题:

我正在尝试使用上述代码实现UNDO方法:尝试从HashMap pathmap中删除thelastLindId键(并将其放入HashMap reservedpathMap以供稍后 Redo 使用),这样当调用invalidate()时,它将调用OnDraw()并通过重新绘制来使其生效。

for (Integer key : pathMap.keySet()) 
                canvas.drawPath(pathMap.get(key), paintLine); 

然而,按下撤销按钮可以触发"已点击撤销"的提示,但最后画的线条未能消失。

请问有人能给我关于Undo()和Redo()的提示吗?非常感谢!


你确定这段代码确实在删除最后一行吗?你有检查过哈希表的大小和其中的值吗? - hardartcore
我刚在TouchEnded方法中添加了Toast.makeText(getContext(), "touchEnded" + pathMap.size(), Toast.LENGTH_SHORT).show();尝试绘制以显示toast。我发现当使用1个手指第一次绘制时,它显示大小=1,但是当使用1个手指继续绘制第二条线时,它仍然显示大小=1。然后我进一步尝试同时使用2个手指进行第3和第4条线的绘制,它会显示大小=2。使用1个手指绘制第5条线的大小显示为2。使用3个手指绘制第6、7、8条线时,它显示大小=3。我真的不知道为什么。 - pearmak
1个回答

1
我理解您想实现的是,在画布上绘制线条并添加撤销功能。首先,我认为应该在用户抬起手指时,在touchEnded方法中将路径添加到数组中。其次,我不太明白您所解释的关于两个/三个手指的事情?您是否支持画布上的多点触控?这是我之前在一些示例中使用的实现方式,用于在画布上绘制并实现撤销功能。希望它能帮助您更清楚地了解这些内容:
public void onClickUndo () { 
if (paths.size()>0) { 
   undonePaths.add(paths.remove(paths.size()-1))
   invalidate();
 }
    else
     //toast the user 
}

public void onClickRedo (){
   if (undonePaths.size()>0) { 
       paths.add(undonePaths.remove(undonePaths.size()-1)) 
       invalidate();
   } 
   else 
     //toast the user 
}

以下是您的触摸方法的等效方式:

@Override
protected void onSizeChanged(int w, int h, int oldw, int oldh) {
    super.onSizeChanged(w, h, oldw, oldh);
}

@Override
protected void onDraw(Canvas canvas) {            

    for (Path p : paths){
        canvas.drawPath(p, mPaint);
    }

}

private float mX, mY;
private static final float TOUCH_TOLERANCE = 0;

private void touch_start(float x, float y) {
    mPath.reset();
    mPath.moveTo(x, y);
    mX = x;
    mY = y;
}
private void touch_move(float x, float y) {
    float dx = Math.abs(x - mX);
    float dy = Math.abs(y - mY);
    if (dx >= TOUCH_TOLERANCE || dy >= TOUCH_TOLERANCE) {
        mPath.quadTo(mX, mY, (x + mX)/2, (y + mY)/2);
        mX = x;
        mY = y;
    }
}
private void touch_up() {
    mPath.lineTo(mX, mY);
    // commit the path to our offscreen
    mCanvas.drawPath(mPath, mPaint);
    // kill this so we don't double draw            
    mPath = new Path();
    paths.add(mPath);
}

从这里可以看出,paths是我存储路径的ArrayList。如果您告诉我为什么需要将路径放入HashMap中,我可能会更有帮助。


非常感谢您详细的回答!对于我上面提到的2或3个手指,是的,绘图视图支持多点触控,并且当同时使用2个手指时,Toast报告哈希映射表的大小为2,如果同时使用3个手指进行绘制,则大小为3。之后,如果只使用1个手指返回,它仍将显示大小=3。 - pearmak
我刚刚使用你上面的代码编写了一个非多点触控绘图代码。使用路径数组一切都正常。但是当我像你上面展示的那样实现撤销时,它不起作用,并且出现了两个问题,如https://dev59.com/6G7Xa4cB1Zd3GeqPsKbG所示,想知道你是否有任何线索=)非常感谢!! - pearmak

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