在
这是我的实现,基本上遵循了 扩展现有用户模型 的说明:
然而,在进行
django.contrib.auth.models.User
中,first_name
和 last_name
字段都有 blank=True
。我怎样才能在自己的模型中使它们变为 blank=False, null=False
?这是我的实现,基本上遵循了 扩展现有用户模型 的说明:
models.py
class Fellow(models.Model):
user = models.OneToOneField(
User,
on_delete=models.CASCADE
)
first_name = models.CharField(
_("first_name"),
max_length=30,
)
last_name = models.CharField(
_("last_name"),
max_length=30,
)
# other fields omitted
from . import signals
signals.py
from django.contrib.auth.models import User
from django.db.models.signals import post_save
from django.dispatch import receiver
from .models import Fellow
@receiver(post_save, sender=User)
def create_fellow_on_user_create(sender, instance, created, **kwargs):
if created:
Fellow.objects.create(user=instance)
然而,在进行
python manage.py shell
测试时,我遇到了一个错误:>>> f = Fellow.objects.create(username='username', password='passwd')
Traceback (most recent call last):
File "<console>", line 1, in <module>
File "/Users/sunqingyao/Envs/django_tutorial/lib/python3.6/site-packages/django/db/models/manager.py", line 85, in manager_method
return getattr(self.get_queryset(), name)(*args, **kwargs)
File "/Users/sunqingyao/Envs/django_tutorial/lib/python3.6/site-packages/django/db/models/query.py", line 392, in create
obj = self.model(**kwargs)
File "/Users/sunqingyao/Envs/django_tutorial/lib/python3.6/site-packages/django/db/models/base.py", line 571, in __init__
raise TypeError("'%s' is an invalid keyword argument for this function" % list(kwargs)[0])
TypeError: 'username' is an invalid keyword argument for this function
User
派生子类吗?但是文档中的示例代码写的是class Employee(models.Model):
而不是class Employee(User):
... - nalzokdjango.core.exceptions.FieldError: Fellow 类中的本地字段 'first_name' 与基类 'User' 中同名的字段冲突。
- nalzok