通过以上答案和建议的帮助,我已经获得了结果。
以下是解决方案:
创建一个正则表达式制作函数。
public static ArrayList<String> listOfPattern()
{
ArrayList<String> listOfPattern=new ArrayList<String>();
String ptVisa = "^4[0-9]$";
listOfPattern.add(ptVisa);
String ptMasterCard = "^5[1-5]$";
listOfPattern.add(ptMasterCard);
String ptDiscover = "^6(?:011|5[0-9]{2})$";
listOfPattern.add(ptDiscover);
String ptAmeExp = "^3[47]$";
listOfPattern.add(ptAmeExp);
return listOfPattern;
}
Integer[] imageArray = { R.drawable.visa, R.drawable.master, R.drawable.disnet, R.drawable.ae };
在 addTextChangedListener 中使用以下代码:
creditcardnumberedittext.addTextChangedListener(new TextWatcher()
{
@Override
public void onTextChanged(CharSequence s, int start, int before, int count)
{
String ccNum = s.toString();
if(ccNum.length()>=2)
{
for (int i = 0; i < listOfPattern.size(); i++)
{
if (ccNum.substring(0, 2).matches(listOfPattern.get(i)))
{
creditcardnumberedittext.setCompoundDrawablesWithIntrinsicBounds(0, 0, imageArray[i], 0);
cardtype = String.valueOf(i);
}
}
}
}
@Override
public void beforeTextChanged(CharSequence s, int start, int count, int after)
{
}
@Override
public void afterTextChanged(Editable s)
{
if (!creditcardnumberedittext.getText().toString().equalsIgnoreCase(""))
{
for (int i = 0; i < listOfPattern.size(); i++)
{
if (creditcardnumberedittext.getText().toString().matches(listOfPattern.get(i)))
{
creditcardnumberedittext.setCompoundDrawablesWithIntrinsicBounds(0, 0, imageArray[i], 0);
cardtype = String.valueOf(i);
}
}
}
else
{
creditcardnumberedittext.setCompoundDrawablesWithIntrinsicBounds(0, 0, R.drawable.allcards, 0);
}
}
});
Thanks..