可扩展列表适配器中的子项ContextMenu

Question

我正在尝试创建一个ContextMenu，如果用户长按一个ExpandableListAdater的项目（组或组子项），但ContextMenu仅在组项目上长按时显示，而不是在组子项上:

创建：

@Override
protected void onCreate(Bundle savedInstanceState) {
    //...
    setListAdapter(mAdapter);
    registerForContextMenu(getExpandableListView());

onCreateContextMenu:

@Override
public void onCreateContextMenu(ContextMenu menu, View v, ContextMenuInfo menuInfo) {
    super.onCreateContextMenu(menu, v, menuInfo);
    Log.i("", "Click");
    ExpandableListView.ExpandableListContextMenuInfo info = (ExpandableListView.ExpandableListContextMenuInfo) menuInfo;

    int type = ExpandableListView.getPackedPositionType(info.packedPosition);
    int groupPosition = ExpandableListView.getPackedPositionGroup(info.packedPosition);
    int childPosition = ExpandableListView.getPackedPositionChild(info.packedPosition);

    // Show context menu for groups
    if (type == ExpandableListView.PACKED_POSITION_TYPE_GROUP) {
        menu.setHeaderTitle("Group");
        menu.add(0, 0, 1, "Delete");

        // Show context menu for children
    } else if (type == ExpandableListView.PACKED_POSITION_TYPE_CHILD) {
        menu.setHeaderTitle("Child");
        menu.add(0, 0, 1, "Delete");
    }
}

onContextItemSelected:

@Override
public boolean onContextItemSelected(MenuItem item) {
    ExpandableListView.ExpandableListContextMenuInfo info = (ExpandableListView.ExpandableListContextMenuInfo) item
            .getMenuInfo();

    int type = ExpandableListView.getPackedPositionType(info.packedPosition);
    int groupPosition = ExpandableListView.getPackedPositionGroup(info.packedPosition);
    int childPosition = ExpandableListView.getPackedPositionChild(info.packedPosition);

    if (type == ExpandableListView.PACKED_POSITION_TYPE_GROUP) {
        // do something with parent

    } else if (type == ExpandableListView.PACKED_POSITION_TYPE_CHILD) {
        // do someting with child
    }

    return super.onContextItemSelected(item);
}

我觉得我错过了一些东西，因为如果我长按孩子的话，“Click”就不会被记录。我想 onCreateContextMenu 在我长按孩子时没有被调用。我该如何管理为 ExpandableListAdapter 组的子项展示一个 ContextMenu ？

- Kurztipp

Answer 1

解决方案是：

@Override
public boolean isChildSelectable(int groupPosition, int childPosition) {
    // Check your child items here
    return true;
}

自动实现是return false;

- Kurztipp