问题是,指定的变音符号必须被明确地解析,因为独立的双点不存在,所以双引号用于此情况。所以为了解决您的问题,除了实现每个需要的情况之外,您没有其他选择。
这里有一个起点来获取线索...
public SomeFunction()
{
string asciiChars = "Dutch has funny chars: a,e,u";
string diacrits = " ' \" \"";
var combinedChars = asciiChars.Zip(diacrits, (ascii, diacrit) =>
{
return CombineChars(ascii, diacrit);
});
var Result = new String(combinedChars.ToArray());
}
private char CombineChars(char ascii, char diacrit)
{
switch (diacrit)
{
case '"':
return AddDoublePoints(ascii);
case '\'':
return AddAccent(ascii);
default:
return ascii;
}
}
private char AddDoublePoints(char ascii)
{
switch (ascii)
{
case 'a':
return 'ä';
case 'o':
return 'ö';
case 'u':
return 'ü';
default:
return ascii;
}
}
private char AddAccent(char ascii)
{
switch (ascii)
{
case 'a':
return 'á';
case 'o':
return 'ó';
default:
return ascii;
}
}
}
虽然IEnumerable.Zip已经在.Net 4中实现了(链接),但是如果你想在3.5中使用它,你需要这段代码(引用自Eric Lippert):
public static class IEnumerableExtension
{
public static IEnumerable<TResult> Zip<TFirst, TSecond, TResult>
(this IEnumerable<TFirst> first,
IEnumerable<TSecond> second,
Func<TFirst, TSecond, TResult> resultSelector)
{
if (first == null) throw new ArgumentNullException("first");
if (second == null) throw new ArgumentNullException("second");
if (resultSelector == null) throw new ArgumentNullException("resultSelector");
return ZipIterator(first, second, resultSelector);
}
private static IEnumerable<TResult> ZipIterator<TFirst, TSecond, TResult>
(IEnumerable<TFirst> first,
IEnumerable<TSecond> second,
Func<TFirst, TSecond, TResult> resultSelector)
{
using (IEnumerator<TFirst> e1 = first.GetEnumerator())
using (IEnumerator<TSecond> e2 = second.GetEnumerator())
while (e1.MoveNext() && e2.MoveNext())
yield return resultSelector(e1.Current, e2.Current);
}
}