我希望能够在 createChooser() 对话框弹出后检测用户选择的 app。因此,我创建了一个如下所示的 BroadcastReceiver
子类:
import android.content.BroadcastReceiver;
import android.content.Context;
import android.content.Intent;
import android.util.Log;
public class ShareBroadcastReceiver extends BroadcastReceiver {
@Override
public void onReceive(Context context, Intent intent) {
Log.d("INFORMATION", "Received intent after selection: "+intent.getExtras().toString());
}
}
此外,我已将我的接收器添加到了我的Android清单文件中:
<application>
...
...
...
<receiver android:name=".helpers.ShareBroadcastReceiver" android:exported="true"/>
</application>
以下是调用createChooser对话框的代码:
Intent sendIntent = new Intent(android.content.Intent.ACTION_SEND);
sendIntent.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
sendIntent.setType("image/png");
if (android.os.Build.VERSION.SDK_INT >= android.os.Build.VERSION_CODES.LOLLIPOP_MR1) {
Log.d("INFORMATION", "The current android version allow us to know what app is chosen by the user.");
Intent receiverIntent = new Intent(this,ShareBroadcastReceiver.class);
PendingIntent pendingIntent = PendingIntent.getBroadcast(this, 0, receiverIntent, PendingIntent.FLAG_CANCEL_CURRENT);
sendIntent = Intent.createChooser(sendIntent,"Share via...", pendingIntent.getIntentSender());
}
startActivity(sendIntent);
尽管我直接使用
ShareBroadcastReceiver
类名而没有使用任何intent-filter
,这仍然是一个明确的PendingIntent
,但当用户点击选择器对话框后,我的广播接收器并没有被回调,我做错了什么?