我正在尝试将以下JSON转换为Java对象。
{
"Data":[
{
"AccountId":"2009852923",
"Currency":"EUR",
"Nickname":"SA 01",
"Account":{
"SchemeName":"BBAN",
"Name":"SA 01",
"Identification":"2009852923"
},
"Servicer":{
"SchemeName":"BICFI",
"Identification":"FNBSZAJJ"
}
},
{
"AccountId":"1028232942",
"Currency":"EUR",
"Nickname":"FNBCREDIT",
"Account":{
"SchemeName":"BBAN",
"Name":"FNBCREDIT",
"Identification":"1028232942"
},
"Servicer":{
"SchemeName":"BICFI",
"Identification":"FNBSZAJJ"
}
}
],
"Links":{
"self":"http://localhost:3000/api/open-banking/accounts/1009427721/transactions"
},
"Meta":{
"total-pages":1
}
}
使用以下数据传输对象(为简洁起见,未发布参考类)。
public class TransactionDTO {
private Data[] data;
private Links links;
private Meta meta;
public Data[] getData () { return data; }
public void setData (Data[] data) { this.data = data; }
public Links getLinks () { return links; }
public void setLinks (Links links) { this.links = links; }
public Meta getMeta () { return meta; }
public void setMeta (Meta meta) { this.meta = meta; }
}
将DTO转换为Java对象的代码如下:
private TransactionDTO marshall(String accountTransactionsJSON) {
ObjectMapper objectMapper = new ObjectMapper();
TransactionDTO transactionDTO = null;
try {
transactionDTO = objectMapper.readValue(accountTransactionsJSON, TransactionDTO.class);
} catch (IOException e) {
e.printStackTrace();
}
return transactionDTO;
}
我遇到了这个错误:
com.fasterxml.jackson.databind.exc.UnrecognizedPropertyException: Unrecognized field "Data" (class xxx.dto.TransactionDTO), not marked as ignorable (3 known properties: "links", "data", "meta"])
at [Source: java.io.StringReader@48f43b70; line: 2, column: 11] (through reference chain: xxx.dto.TransactionDTO["Data"])
我尝试了不同的方法来解决这个问题,例如:
objectMapper.enable(SerializationFeature.WRAP_ROOT_VALUE);
objectMapper.configure(DeserializationFeature.ACCEPT_SINGLE_VALUE_AS_ARRAY, true);
objectMapper.configure(DeserializationFeature.FAIL_ON_UNKNOWN_PROPERTIES, false);
除此之外:
@JsonRootName(value = "data")
然而,我要么得到同样的问题,要么得到只包含 null 值的 TransactionDTO。
我猜问题出在 Data 字段上,但我不知道如何解决这个问题(这里的解决方案对我也无效)。
问题
- 有没有想法如何解决这个问题?
- 访问器的大小写应该反映 JSON 中的大小写吗?