我开始使用pygame想要制作一个简单的游戏,其中需要一个倒计时器。如何在Pygame中实现倒计时(例如10秒)?
另一种简单的方法是直接使用pygame的事件系统。
这里是一个简单的例子:
import pygame
pygame.init()
screen = pygame.display.set_mode((128, 128))
clock = pygame.time.Clock()
counter, text = 10, '10'.rjust(3)
pygame.time.set_timer(pygame.USEREVENT, 1000)
font = pygame.font.SysFont('Consolas', 30)
run = True
while run:
for e in pygame.event.get():
if e.type == pygame.USEREVENT:
counter -= 1
text = str(counter).rjust(3) if counter > 0 else 'boom!'
if e.type == pygame.QUIT:
run = False
screen.fill((255, 255, 255))
screen.blit(font.render(text, True, (0, 0, 0)), (32, 48))
pygame.display.flip()
clock.tick(60)
在这个页面上,您将找到您要查找的内容:http://www.pygame.org/docs/ref/time.html#pygame.time.get_ticks
在开始倒计时之前,您需要下载一次ticks(这可以是游戏中的触发器 - 键事件等)。
例如:
start_ticks=pygame.time.get_ticks() #starter tick
while mainloop: # mainloop
seconds=(pygame.time.get_ticks()-start_ticks)/1000 #calculate how many seconds
if seconds>10: # if more than 10 seconds close the game
break
print (seconds) #print how many seconds
pygame.time.set_timer()
来重复创建一个USEREVENT
。例如:
timer_interval = 500 # 0.5 seconds
timer_event = pygame.USEREVENT + 1
pygame.time.set_timer(timer_event , timer_interval)
pygame.USEREVENT
(24)和pygame.NUMEVENTS
(32)之间。在这种情况下,pygame.USEREVENT+1
是计时器事件的事件ID。在事件循环中接收事件:
running = True
while running:
for event in pygame.event.get():
if event.type == pygame.QUIT:
running = False
elif event.type == timer_event:
# [...]
查看示例:
import pygame
pygame.init()
window = pygame.display.set_mode((200, 200))
clock = pygame.time.Clock()
font = pygame.font.SysFont(None, 100)
counter = 10
text = font.render(str(counter), True, (0, 128, 0))
timer_event = pygame.USEREVENT+1
pygame.time.set_timer(timer_event, 1000)
run = True
while run:
clock.tick(60)
for event in pygame.event.get():
if event.type == pygame.QUIT:
run = False
elif event.type == timer_event:
counter -= 1
text = font.render(str(counter), True, (0, 128, 0))
if counter == 0:
pygame.time.set_timer(timer_event, 0)
window.fill((255, 255, 255))
text_rect = text.get_rect(center = window.get_rect().center)
window.blit(text, text_rect)
pygame.display.flip()
pygame.time.Clock.tick
返回自上一次 clock.tick
调用以来的毫秒数(delta time, dt
),因此您可以使用它来增加或减少计时器变量。
import pygame as pg
def main():
pg.init()
screen = pg.display.set_mode((640, 480))
font = pg.font.Font(None, 40)
gray = pg.Color('gray19')
blue = pg.Color('dodgerblue')
# The clock is used to limit the frame rate
# and returns the time since last tick.
clock = pg.time.Clock()
timer = 10 # Decrease this to count down.
dt = 0 # Delta time (time since last tick).
done = False
while not done:
for event in pg.event.get():
if event.type == pg.QUIT:
done = True
timer -= dt
if timer <= 0:
timer = 10 # Reset it to 10 or do something else.
screen.fill(gray)
txt = font.render(str(round(timer, 2)), True, blue)
screen.blit(txt, (70, 70))
pg.display.flip()
dt = clock.tick(30) / 1000 # / 1000 to convert to seconds.
if __name__ == '__main__':
main()
pg.quit()
你可以通过多种方式实现这一点,以下是其中一种方法。据我所知,Python没有中断机制。
import time, datetime
timer_stop = datetime.datetime.utcnow() +datetime.timedelta(seconds=10)
while True:
if datetime.datetime.utcnow() > timer_stop:
print "timer complete"
break
有很多方法可以做到这一点,这只是其中之一。
import pygame,time, sys
from pygame.locals import*
pygame.init()
screen_size = (400,400)
screen = pygame.display.set_mode(screen_size)
pygame.display.set_caption("timer")
time_left = 90 #duration of the timer in seconds
crashed = False
font = pygame.font.SysFont("Somic Sans MS", 30)
color = (255, 255, 255)
while not crashed:
for event in pygame.event.get():
if event.type == QUIT:
crashed = True
total_mins = time_left//60 # minutes left
total_sec = time_left-(60*(total_mins)) #seconds left
time_left -= 1
if time_left > -1:
text = font.render(("Time left: "+str(total_mins)+":"+str(total_sec)), True, color)
screen.blit(text, (200, 200))
pygame.display.flip()
screen.fill((20,20,20))
time.sleep(1)#making the time interval of the loop 1sec
else:
text = font.render("Time Over!!", True, color)
screen.blit(text, (200, 200))
pygame.display.flip()
screen.fill((20,20,20))
pygame.quit()
sys.exit()
这其实很简单。感谢 Pygame 创建了一个简单的库!
import pygame
x=0
while x < 10:
x+=1
pygame.time.delay(1000)
就是这样了!玩得开心,享受pygame!
另一种方法是设置一个新的USEREVENT来进行计时,设置时间间隔,然后将事件放入游戏循环中。
import pygame
from pygame.locals import *
import sys
pygame.init()
#just making a window to be easy to kill the program here
display = pygame.display.set_mode((300, 300))
pygame.display.set_caption("tick tock")
#set tick timer
tick = pygame.USEREVENT
pygame.time.set_timer(tick,1000)
while 1:
for event in pygame.event.get():
if event.type == QUIT:
pygame.quit()
sys.exit()
if event.type == pygame.USEREVENT:
if event.type == tick:
## do whatever you want when the tick happens
print('My tick happened')