I have the following javascript object:
Person1.Name = "John";
Person1.Age = 12;
Person2.Name = "Joe";
Person2.Age = 5;
我有一个人的数组,如何根据年龄查找最小/最大值?
任何JavaScript或Jquery的解决方案都可以接受。
非常感谢您的帮助。
I have the following javascript object:
Person1.Name = "John";
Person1.Age = 12;
Person2.Name = "Joe";
Person2.Age = 5;
假设你的数组长这样:
var persons = [{Name:"John",Age:12},{Name:"Joe",Age:5}];
然后您可以:
var min = Math.min.apply(null, persons.map(function(a){return a.Age;}))
,max = Math.max.apply(null, persons.map(function(a){return a.Age;}))
[编辑] 添加了ES2015方法:
const minmax = (someArrayOfObjects, someKey) => {
const values = someArrayOfObjects.map( value => value[someKey] );
return {
min: Math.min.apply(null, values),
max: Math.max.apply(null, values)
};
};
console.log(
minmax(
[ {Name: "John", Age: 12},
{Name: "Joe", Age: 5},
{Name: "Mary", Age: 3},
{Name: "James sr", Age: 93},
{Name: "Anne", Age: 33} ],
'Age')
);
首先,您需要使用自定义排序函数对数组进行排序:
var sorted = persons.sort(function(a, b) {
if(a.Age > b.Age) return 1;
else if(a.Age < b.Age) return -1;
else return 0;
});
然后你可以只取第一个和最后一个:
var min = sorted[0],
max = sorted[sorted.length - 1];