我不知道哪里出了问题，非常感谢您的帮助！在尝试登录后，我收到了“身份验证方法不支持：GET”的消息。
这是我的security-Context.xml文件：
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:security="http://www.springframework.org/schema/security"
xmlns:tx="http://www.springframework.org/schema/tx"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/security
http://www.springframework.org/schema/security/spring-security-3.1.xsd">
<!-- <security:http auto-config="true" access-decision-manager-ref="accessDecisionManager"> -->
<security:http auto-config="true">
<security:intercept-url pattern="/login/login.do" access="IS_AUTHENTICATED_ANONYMOUSLY" />
<security:intercept-url pattern="/login/doLogin.do" access="IS_AUTHENTICATED_ANONYMOUSLY" />
<security:intercept-url pattern="/lib/**" access="IS_AUTHENTICATED_ANONYMOUSLY" />
<security:intercept-url pattern="/css/**" access="IS_AUTHENTICATED_ANONYMOUSLY" />
<security:intercept-url pattern="/images/**" access="IS_AUTHENTICATED_ANONYMOUSLY" />
<security:intercept-url pattern="/resources/**" access="IS_AUTHENTICATED_ANONYMOUSLY" />
<security:intercept-url pattern="/**" access="IS_AUTHENTICATED_REMEMBERED" />
<security:form-login login-page="/login/login.do" authentication-failure-url="/login/login.do?login_error=true" default-target-url="/test/showTest.do"/>
<security:logout logout-success-url="/login/login.do" invalidate-session="true" />
<security:remember-me key="rememberMe"/>
</security:http>
<security:authentication-manager>
<security:authentication-provider>
<security:jdbc-user-service data-source-ref="dataSource"
users-by-username-query="select EMAIL as email, PASSWORD as password, from ams.user where EMAIL=?"
authorities-by-username-query="
select distinct user.EMAIL as email, permission.NAME as authority
from ams.user, ams.user_role, ams.role, ams.role_permission, ams.permission
where user.ID=user_role.USER_ID AND user_role.ROLE_ID=role_permission.ROLE_ID AND role_permission.PERMISSION_ID=permission.ID AND user.EMAIL=?"/>
<security:password-encoder ref="passwordEncoder" />
</security:authentication-provider>
</security:authentication-manager>
<bean id="passwordEncoder"
class="org.springframework.security.authentication.encoding.ShaPasswordEncoder">
<constructor-arg value="256" />
</bean>
</beans>
以下是我的LoginController代码：
@Controller
public class LoginController {
@RequestMapping(method = RequestMethod.GET)
public ModelAndView showLogin() {
ModelAndView mav = new ModelAndView("login/login");
return mav;
}
@RequestMapping(method = RequestMethod.POST)
public ModelAndView doLogin(@RequestParam("email") String email,
@RequestParam("password") String password,
@RequestParam("remember_me") boolean rememberMe,
HttpServletRequest request, HttpServletResponse response) {
ModelAndView mav = new ModelAndView();
mav.setViewName("redirect:/j_spring_security_check?j_email=" + email + "&j_password=" + password + "&_spring_security_remember_me=" + rememberMe);
return mav;
}
}
如果您需要更多帮助，请告诉我。
doLogin()方法正在处理一个POST请求并发送重定向作为响应。然后客户端（浏览器）会向重定向消息中指定的URL发送GET请求（这是一个手工制作的登录URL）。 - zagyi<form action="/j_spring_security_check" method="post">- zagyi