ANTLR 4 - 不匹配的输入

4

我正在尝试使用ANTLR为我的一个项目开发一个小型DSL。因此,我编写了词法分析器的定义...

lexer grammar SpamkillerLexer;

MAILBOX: 'Mailbox';
PASSWORD: 'Password';
HOST: 'Host';
USER: 'User';
FOLDER: 'Folder';
PORT: 'Port';
ACTIONS: 'Actions';

WHEN: 'When';
SUBJECT: 'Subject';
BODY: 'Body';
EQUALS: 'Equals';
CONTAINS: 'Contains';
THEN: 'Then';
DELETE: 'Delete';
REDIRECT: 'Redirect';
TO: 'to';

BR_OP: '{';
BR_CL: '}';
EQ: '=';

STRING: '"' ( '\\"' | . )*? '"';
LITERAL: [a-zA-Z_0-9]+;

WS : [ \n\t\r]+ -> skip ;

...并且解析器...

parser grammar SpamkillerParser;
mailboxes: mailbox+;
mailbox: MAILBOX LITERAL BR_OP settings BR_CL;

settings: setting+;
setting: (key EQ STRING | ACTIONS EQ actions);
key: MAILBOX | PASSWORD | HOST | USER | FOLDER | PORT;

actions: BR_OP action* BR_CL;
action: WHEN condition THEN job;
condition: (SUBJECT | BODY) (EQUALS | CONTAINS) STRING;
job: (DELETE | (REDIRECT TO STRING));

我的测试文件看起来像这样:

Mailbox Foobar {
    Port = "123"
    Host = "foohost"
    User = "foouser"
    Password = "foopass"
    Folder = "Inbox"
    Actions = {
        When Subject Equals "fooooo" Then Delete
        When Body Contains "fooooo" Then Redirect to "foo@bar.baz"
    }
}

当我在ANTLR IntelliJ插件中测试邮件箱(mailboxes)时,它运行得很完美,我也获取到了相应的AST(抽象语法树):

AST

但是当我尝试通过程序解析我的测试文件时,却遇到了错误...
line 1:8 mismatched input 'Foobar' expecting LITERAL

我尝试重新排序我的词法规则,但无论如何都不能摆脱错误。有人知道如何解决吗?

我用以下代码来解析我的文件:

String input = FileUtils.readFileToString(new File("test.txt"), Charsets.UTF_8);
CodePointCharStream inputStream = CharStreams.fromString(input);
SpamkillerLexer lexer = new SpamkillerLexer(inputStream);
CommonTokenStream commonTokenStream = new CommonTokenStream(lexer);
SpamkillerParser parser = new SpamkillerParser(commonTokenStream);
SpamkillerParser.MailboxesContext mailboxes = parser.mailboxes();
1个回答

2
你的解析器中没有指定要使用哪个标记词汇表。因此,ANTLR会为你的解析器创建隐式标记(实际上是简单的终端符号),而不是使用词法分析器中的标记。
要解决这个问题,请提供tokenVocab选项:
parser grammar SpamkillerParser;

options {
   tokenVocab=SpamkillerLexer;
}

mailboxes: mailbox+;
mailbox: MAILBOX LITERAL BR_OP settings BR_CL;

settings: setting+;
setting: (key EQ STRING | ACTIONS EQ actions);
key: MAILBOX | PASSWORD | HOST | USER | FOLDER | PORT;

actions: BR_OP action* BR_CL;
action: WHEN condition THEN job;
condition: (SUBJECT | BODY) (EQUALS | CONTAINS) STRING;
job: (DELETE | (REDIRECT TO STRING));

那解决了我的问题 :) 非常感谢! - C.M.

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