列表推导式用于合并两个列表

Question

我有两个序列，如下所示：

t = [[1,2,3],[4,5,6],[7,8,9]]
alpha = ['a','b','c']

如何使用列表推导式将 t 修改为以下内容：-

t = [[1,2,3,'a'],[4,5,6,'b'],[7,8,9,'c']]

- Vaibhav

Answer 1

use zip:

t = [[1,2,3],[4,5,6],[7,8,9]]
alpha = ['a','b','c']
new_list = [a+[b] for a, b in zip(t, alpha)]

输出：

[[1, 2, 3, 'a'], [4, 5, 6, 'b'], [7, 8, 9, 'c']]

- Ajax1234

Answer 2

您可以使用zip函数获取相应元素的对，然后只需将它们连接起来即可:

>>> t = [[1,2,3],[4,5,6],[7,8,9]]
>>> alpha = ['a','b','c']
>>> [x[0] + [x[1]] for x in zip(t,alpha)]
[[1, 2, 3, 'a'], [4, 5, 6, 'b'], [7, 8, 9, 'c']]

- Mureinik

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这似乎是最符合Python风格的方法。这是一个清晰的列表推导式，可用于其他需要迭代和操作两个列表的情况。 - David Kamer

Answer 3

遍历索引:

t = [[1,2,3],[4,5,6],[7,8,9]]
alpha = ['a','b','c']
print([t[i] + [alpha[i]] for i in range(len(alpha))])

- Jeremy McGibbon