我需要知道我编译的libjpeg是32位还是64位体系结构,但不知道如何找到,是否有命令可以让我检查?
我需要知道我编译的libjpeg是32位还是64位体系结构,但不知道如何找到,是否有命令可以让我检查?
只需输入file libjpeg.dylib
,您将得到以下输出
libpoll.dylib: Mach-O universal binary with 3 architectures
libpoll.dylib (for architecture x86_64): Mach-O 64-bit dynamically linked shared library x86_64
libpoll.dylib (for architecture i386): Mach-O dynamically linked shared library i386
libpoll.dylib (for architecture ppc7400): Mach-O dynamically linked shared library ppc
file
命令可以完美地工作。或者,您可以使用otool
打印fat headers。
$ otool -vf /usr/lib/libSystem.B.dylib
Fat headers
fat_magic FAT_MAGIC
nfat_arch 2
architecture ppc
cputype CPU_TYPE_POWERPC
cpusubtype CPU_SUBTYPE_POWERPC_ALL
offset 4096
size 2221800
align 2^12 (4096)
architecture ppc64
cputype CPU_TYPE_POWERPC64
cpusubtype CPU_SUBTYPE_POWERPC64_ALL
offset 2228224
size 2169980
align 2^12 (4096)
file
命令:[mqudsi@iqudsi:Xcode/FSLogger]$ file ./original (07-31 02:53)
./original: Mach-O executable i386