我有一个字符串列表
a = ['word1, 23, 12','word2, 10, 19','word3, 11, 15']
我想创建一个列表
b = [['word1',23,12],['word2', 10, 19],['word3', 11, 15]]
这是一个简便的方法吗?
input = ['word1, 23, 12','word2, 10, 19','word3, 11, 15']
output = []
for item in input:
items = item.split(',')
output.append([items[0], int(items[1]), int(items[2])])
试试这个:
b = [ entry.split(',') for entry in a ]
b = [ b[i] if i % 3 == 0 else int(b[i]) for i in xrange(0, len(b)) ]
def parseString(string):
try:
return int(string)
except ValueError:
return string
b = [[parseString(s) for s in clause.split(', ')] for clause in a]
<string>, <int>, <int>
,您可以更加简洁:def parseClause(a,b,c):
return [a, int(b), int(c)]
b = [parseClause(*clause) for clause in a]
b = []
for x in a:
temp = []
items = x.split(",")
for item in items:
try:
n = int(item)
except ValueError:
temp.append(item)
else:
temp.append(n)
b.append(temp)
这个答案比其他的长,但更加灵活多变。
我知道这已经旧了,但这里是一个只有一行的列表推导式:
data = ['word1, 23, 12','word2, 10, 19','word3, 11, 15']
[[int(item) if item.isdigit() else item for item in items.split(', ')] for items in data]
or
[int(item) if item.isdigit() else item for items in data for item in items.split(', ')]