如何从JSONArray中删除特定元素？

Question

如何从JSONArray中删除特定元素？

43

我正在开发一个应用程序，从服务器请求一个PHP文件。这个PHP文件返回一个JSONArray，其中包含JSONObjects作为其元素，例如：

[ 
  {
    "uniqid":"h5Wtd", 
    "name":"Test_1", 
    "address":"tst", 
    "email":"ru_tst@tst.cc", 
    "mobile":"12345",
    "city":"ind"
  },
  {...},
  {...},
  ...
]

我的代码：

/* jArrayFavFans is the JSONArray i build from string i get from response.
   its giving me correct JSONArray */
JSONArray jArrayFavFans=new JSONArray(serverRespons);
for (int j = 0; j < jArrayFavFans.length(); j++) {
  try {
    if (jArrayFavFans.getJSONObject(j).getString("uniqid").equals(id_fav_remov)) {
      //jArrayFavFans.getJSONObject(j).remove(j); //$ I try this to remove element at the current index... But remove doesn't work here ???? $
      //int index=jArrayFavFans.getInt(j);
      Toast.makeText(getParent(), "Object to remove...!" + id_fav_remov, Toast.LENGTH_SHORT).show();
    }
  } catch (JSONException e) {
    // TODO Auto-generated catch block
    e.printStackTrace();
  }
}

我该如何从这个JSONArray中删除特定元素？

- Rupesh Yadav

11个回答

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- Mahesh · Answer 1

删除多个职位

    public static void main(String[] args) throws JSONException {
        JSONArray array = new JSONArray();
        array.put(0, "0");
        array.put(1, "1");
        array.put(2, "2");
        array.put(3, "3");
        List<Integer> toRemove = new ArrayList<>();
        toRemove.add(1);
        toRemove.add(0);
        toRemove = toRemove.stream().sorted().collect(Collectors.toList());
        int removedCount = 0; // Once we remove the element from array, we should reduce the position also with the removed item size
        for (int position : toRemove) {
            int newPosition = position - removedCount;
            array.remove(newPosition);
            removedCount = removedCount + 1;
            
        }
        System.out.println(array.toString());// ["2","3"]
    }