我正试图弄清如何正确使用JS Test Driver的assertException方法。根据谷歌的文档,它应该是:assertException([msg],callback,error)。但是,无论我做什么,这个测试总是出错(而不是[通过],因为有异常):
ComponentTest.prototype.testEnforceUniqueComponentIds = function() {
assertException(function(){
this.component = new myNamespace.component(this.testComponentSettings);
});
}
在我的src JS文件中:
myNamespace.component = function(params){
if (typeof params.selector == 'undefined'){
throw new Error('no selector provided');
}
this.settings = jQuery.extend({}, {
id : 'defaultComponentId',
type : 'defaultComponentType',
selector : 'body',
isUnique : false
}, params);
if(typeof(myNamespace.componentRegistry[params.id]) === "undefined"){
myNamespace.registerComponent(this);
} else {
throw new Error('non-unique component id provided');
}
}
这是来自js-test-driver的输出结果:
C:\xampp2\htdocs\myNamespace\v2>java -jar JsTestDriver.jar --tests all --verbose
[PASSED] ComponentTest.testInit
[LOG] setUp
[LOG] tearDown
[PASSED] ComponentTest.testDestroy
[LOG] setUp
[LOG] tearDown
[ERROR] ComponentTest.testEnforceUniqueComponentIds
[LOG] setUp
Total 3 tests (Passed: 2; Fails: 0; Errors: 1) (1.00 ms)
Firefox 7.0.1: Run 3 tests (Passed: 2; Fails: 0; Errors 1) (1.00 ms)
ComponentTest.testEnforceUniqueComponentIds error (1.00 ms):
我实在想不出如何让assertException回调中的代码抛出异常,而不会导致测试中出现ERROR - 难道这不是应该发生的吗?
如果有帮助,将不胜感激。