使用OpenWeatherMap API密钥

Question

使用OpenWeatherMap API密钥

4

我得到了一个异常 "http://api.openweathermap.org/data/2.5/weather?q=Sydney"。请问有人可以帮助如何使用它。当我粘贴以下内容时，在网页浏览器中正常工作： http://api.openweathermap.org/data/2.5/weather?q=Sydney&APPID=ea574594b9d36ab688642d5fbeab847e 我也尝试了一下组合，但没有成功。

connection.addRequestProperty("x-api-key",
                    "&APPID=cea574594b9d36ab688642d5fbeab847e");


private static final String OPEN_WEATHER_MAP_API =
        "http://api.openweathermap.org/data/2.5/weather?q=%s";


public static JSONObject getJSON(String city) {
    try {
        URL url = new URL(String.format(OPEN_WEATHER_MAP_API, city));

        HttpURLConnection connection = (HttpURLConnection) url.openConnection();

        connection.addRequestProperty("x-api-key",
                "cea574594b9d36ab688642d5fbeab847e");

        BufferedReader reader =
                new BufferedReader(new InputStreamReader(connection.getInputStream()));

        StringBuffer json = new StringBuffer(1024);
        String tmp = "";

        while((tmp = reader.readLine()) != null)
            json.append(tmp).append("\n");
        reader.close();

        JSONObject data = new JSONObject(json.toString());

        if(data.getInt("cod") != 200) {
            System.out.println("Cancelled");
            return null;
        }

        return data;
    } catch (Exception e) {

        System.out.println("Exception "+ e.getMessage());
        return null;
    }

- Riaz Ud Din

你的API密钥应该作为GET参数传递，而不是使用x-api-key这个意思不明确的参数名。 - njzk2

4个回答

2

看起来Open Weather可能遇到了问题。我这么说是因为他们给出的示例返回与你的相同的错误消息。

来自他们的网站 >>http://openweathermap.org/appid

API调用示例（没有有效密钥）：

api.openweathermap.org/data/2.5/forecast/city?id=524901&APPID=1111111111

- Rickest Rick

1111111111 不是一个有效的密钥，请尝试使用这个 cea574594b9d36ab688642d5fbeab847e ，然后它就可以工作了。 - Riaz Ud Din

3

抱歉，开头多了一个“c”，这是正确的链接：http://api.openweathermap.org/data/2.5/forecast/city?id=524901&APPID=ea574594b9d36ab688642d5fbeab847e - Riaz Ud Din

1

试试这个

Create a class named GetData

class GetData extends AsyncTask <String,Void,String> {

        @Override
        protected String doInBackground(String... params) {
            // TODO Auto-generated method stub
            String result = "";
            HttpURLConnection conn = null;
            try {
                URL url = new URL("http://api.openweathermap.org/data/2.5/weather?q="+URLEncoder.encode(params[0], "UTF-8")+"&APPID=ea574594b9d36ab688642d5fbeab847e");
                conn = (HttpURLConnection) url.openConnection();
                InputStream in = new BufferedInputStream(conn.getInputStream());
                if (in != null) {
                    BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(in));
                    String line = "";

                    while ((line = bufferedReader.readLine()) != null)
                        result += line;
                }
                in.close();
                return result;
            } catch (IOException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }
            finally {
                if(conn!=null)
                conn.disconnect();
            }
            return result;
        }

        @Override
        protected void onPostExecute(String result) {
            // TODO Auto-generated method stub
            super.onPostExecute(result);
            Toast.makeText(getApplicationContext(), result, Toast.LENGTH_LONG).show();
        }

}

And then use this to get the data

new Getdata().execute("your city or country");

- Deepak Goyal

是的，它只适用于悉尼，它将是静态的，我希望它是动态的。 - Riaz Ud Din

我已经添加了编码模式。 - Deepak Goyal

0

Retrofit 的工作示例

    val apiService = 
    API.getInstance().retrofit.create(MyApiEndpointInterface::class.java)

    val params = HashMap<String, String>()
    params["q"] =  "London,uk"
    params["APPID"] = "b6907d289e10d714a6e88b30761fae22"

    val call = apiService.getUser(params)

    call.enqueue(object : Callback<WeatherResponse> {
        override fun onFailure(call: Call<WeatherResponse>?, t: Throwable?) {
            Log.e("Error:::","Error "+t!!.message)
        }

        override fun onResponse(call: Call<WeatherResponse>?, response: Response<WeatherResponse>?) {
            if (response != null && response.isSuccessful && response.body() != null) {
                Log.e("SUCCESS:::","Response "+ response.body()!!.main.temp)

               // val tempCel = ((response.body()!!.main.temp - 32)*5)/9
                val tempCel = (response.body()!!.main.temp  - 273.15f)

                temperature.setText("${tempCel.roundToInt()}°C")

            }
        }

    })

- Hitesh Sahu

网页内容由stack overflow 提供, 点击上面的

可以查看英文原文，
原文链接

- JoCuTo · Accepted Answer

1. 在您的应用程序中添加互联网权限。如何向Android应用程序添加清单权限？

2. 这里有一个关于如何实现API调用的示例。

 public class MainActivity extends Activity {

    JSONObject data = null;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
        getJSON("Sydney");
    }

    public void getJSON(final String city) {

        new AsyncTask<Void, Void, Void>() {


            @Override
            protected void onPreExecute() {
                super.onPreExecute();

            }

            @Override
            protected Void doInBackground(Void... params) {
                try {
                    URL url = new URL("http://api.openweathermap.org/data/2.5/weather?q="+city+"&APPID=ea574594b9d36ab688642d5fbeab847e");

                    HttpURLConnection connection = (HttpURLConnection) url.openConnection();

                    BufferedReader reader =
                            new BufferedReader(new InputStreamReader(connection.getInputStream()));

                    StringBuffer json = new StringBuffer(1024);
                    String tmp = "";

                    while((tmp = reader.readLine()) != null)
                        json.append(tmp).append("\n");
                    reader.close();

                    data = new JSONObject(json.toString());

                    if(data.getInt("cod") != 200) {
                        System.out.println("Cancelled");
                        return null;
                    }


                } catch (Exception e) {

                    System.out.println("Exception "+ e.getMessage());
                    return null;
                }

                return null;
            }

            @Override
            protected void onPostExecute(Void Void) {
            if(data!=null){
                Log.d("my weather received",data.toString());
            }

            }
        }.execute();

    }
}