我希望同时更新多个表,因此我使用了LEFT JOIN来创建一个单独的UPDATE查询。我尝试了两种方法来进行LEFT JOIN,但都失败了。我不知道自己哪里出错了,所以希望有人能够仔细分析这个查询并指出错误。
我已经对查询应用了一些格式化,使其比以前更易读:
首先是:
第二个是:
我已经对查询应用了一些格式化,使其比以前更易读:
首先是:
"UPDATE "
.
"table1 AS t1 SET t1.Bid = :id "
.
"LEFT JOIN table2 AS t2 SET t2.id = :id ON t1.Bid = t2.id AND t1.status = t2.status "
.
"LEFT JOIN table3 AS t3 SET t3.Bid = :id ON t1.Bid = t3.Bid AND t1.status = t3.status "
.
"LEFT JOIN table4 AS t4 SET t4.id = :id ON t1.Bid = t4.id AND t1.status = t4.status "
.
"LEFT JOIN table5 AS t5 SET t5.Bid = :id ON t1.Bid = t5.Bid AND t1.status = t5.status "
.
"LEFT JOIN table6 AS t6 SET t6.id = :id ON t1.Bid = t6.id AND t1.status = t6.status "
.
"LEFT JOIN table7 AS t7 SET t7.Bid = :id ON t1.Bid = t7.Bid AND t1.status = t7.status "
.
"LEFT JOIN table8 AS t8 SET t8.id = :id ON t1.Bid = t8.id AND t1.status = t8.status "
.
"WHERE t1.Bid = :oldid AND t1.status = :status "
第二个是:
$stmt = $dbh - > prepare("UPDATE "
.
"table1 AS t1 "
.
"LEFT JOIN table2 AS t2 ON t1.Bid = t2.id AND t1.status = t2.status "
.
"LEFT JOIN table3 AS t3 ON t1.Bid = t3.Bid AND t1.status = t3.status "
.
"LEFT JOIN table4 AS t4 ON t1.Bid = t4.id AND t1.status = t4.status "
.
"LEFT JOIN table5 AS t5 ON t1.Bid = t5.Bid AND t1.status = t5.status "
.
"LEFT JOIN table6 AS t6 ON t1.Bid = t6.id AND t1.status = t6.status "
.
"LEFT JOIN table7 AS t7 ON t1.Bid = t7.Bid AND t1.status = t7.status "
.
"LEFT JOIN table8 AS t8 ON t1.Bid = t8.id AND t1.status = t8.status "
.
" SET t1.Bid = :id, "
.
" SET t2.id = :id, "
.
" SET t3.Bid = :id, "
.
" SET t4.id = :id, "
.
" SET t5.Bid = :id, "
.
" SET t6.id = :id, "
.
" SET t7.Bid = :id, "
.
" SET t8.id = :id "
.
"WHERE t1.Bid = :oldid AND t1.status = :status ");
更新
我正在使用第一种选项,但是出现了以下错误:
致命错误:Uncaught exception 'PDOException' with message 'SQLSTATE[42000]:语法错误或访问违规:1064 您的SQL语法有误;请检查与您的MySQL服务器版本相对应的手册以获取正确的语法,位于行1附近的“LEFT JOIN table2 AS t2 SET t2.id ='315-512-613-12'”'
第二个选项得到:
致命错误:Uncaught exception 'PDOException' with message 'SQLSTATE[42000]:语法错误或访问违规:1064 您的SQL语法有误;请检查与您的MySQL服务器版本相对应的手册以获取正确的语法,位于行1附近的“SET t2.id ='315-512-613-123V',SET t3.Bid ='315-512-613-123V',SE'”
UPDATE t1, t2, t3 SET t1.field1=value1, t2.field2=value2 ... WHERE t1.pk=t2.fk ...
гҖӮ - Alex BlexLEFT JOIN
的原因之一。 - guradio