我尝试读取文件中的特定字符串。基本上文件看起来像这样:
S0M6A36A108A180A252A324A36|1|48|89|36|Single|
S0M6A36A108A180A252A324A36|2|43|83|108|Single|
S0M6A36A108A180A252A324A36|3|37|85|180|Single|
S0M6A36A108A180A252A324A36|4|37|93|252|Single|
S0M6A36A108A180A252A324A36|5|43|95|324|Single|
S0M6A36A108A180A252A324A36|6|42|89|36|Single|
[META DATA]
01/10/2015|14:50:27|USA|UWI_N2C34_2|MMS1|FORD35|Bednarek|true|6|0|false|
[QUALITY CAMERA CHECK]
1|1|0|
2|1|0|
3|1|0|
4|1|0|
5|1|0|
6|1|0|
[PRESET]
S0M6A36A108A180A252A324A36|TA|
我需要的是在字符串
|USA|
中间读取国家名称,起始行为:01/10/2015|14:50:27|USA|UWI_N2C34_2|MMS1|FORD35|Bednarek|true|6|0|false|
。为了实现这个目标,我尝试使用正则表达式中的 group 函数。我推断出需要从包含该字符串的特定行开始读取。因此,我编写了以下简短代码:
import os
import string
import re
import sys
import glob
import fileinput
country_pattern = 'MYS','IDN','ZAF', 'THA','TWN','SGP', 'NWZ', 'AUS','ALB','AUT','BEL', 'BGR', 'BIH', 'CHE','CZE', 'DEU', 'DNK', 'ESP','EST','SRB','MDK','MNE','BIH', 'BIH','MNE','FIN', 'FRA', 'GBR','GRC', 'HRV', 'HUN', 'IRL', 'ITA', 'LIE', 'LTU', 'LUX', 'LVA', 'MDA', 'SMR','CYP','NLD','NOR','POL','PRT','ROU','SCG', 'SVK','SVN','SWE','TUR','BRA','CAN','USA','MEX','CHL','ARG','RUS'
pattern = r'(\d+)/(\d+)/(\d+)|(\d+):(\d+):(\d+)|(\S+)|(\S+)|(\S+)|(\S+)|(\S+)|(\S+)|(\d+)|(\d+)|(\S+)|'
src = raw_input("Enter source disk location: ")
src = os.path.dirname(src)
for dir,_,_ in os.walk(src):
file_path = glob.glob(os.path.join(dir,"*.txt"))
for file in file_path:
f = open(file, 'r')
object_name = f.readlines()
f.close()
for line_name_tmp in object_name:
line_name = line_name_tmp.replace('\n','')
if line_name == '':
line_name.split()
continue
else:
try:
searchObj = re.search(pattern, line_name)
m = searchObj.group(7)
if m in country_pattern:
print "searchObj.group(7) : ", searchObj.group(7)
else:
print 'did not find any match'
except:
print line_name
pass
但它总是打印出“未找到任何匹配项”。我错过了什么吗? 谢谢建议。
[META DATA]
为止,并找到其后的一行。然后,我会用ls=line.split('|')
将其分割,并使用country=ls[2]
提取其中的第三个元素。 - Pynchia