我正在学习MIPS汇编语言,因为我有些空闲时间,我试图编写一个程序,将数字推到堆栈上,然后将其弹出。我希望它在遇到负数之前计算弹出的数字数量,并且每次得到一个负数时都计算弹出了多少个负数和正数。
目前为止,我已经写出了以下代码:
#count the number of negative words on the stock by poping the stack until a non- negative word is found
#and print out the number of words found
.text
.globl main
#this code reads the numbers from the data area and stores in them in a stack
#the numbers are located in the test area and the number of numbers in the num area
main: la $t0, test
lw $t1, num
loop: lw $t2,($t0)
sub $sp, $sp, 4
sw $t2($sp)
add $t0, $t0, 4
add $t1, $t1, -1
bnez $t1, loop
#pop from the stack and print the number of numbers in the stack before a nonnegative number is reached
#then keep count of how many negative and positive ones there are total
#code I cannot come up with would go here
.data
test: .word
2, 0xfffabfff,2,-4,-9,0x99999999,0x90000000,-2147479536,0x80000000
num: .word 10
ans: .asciiz "Number is = "
endl: .asciiz "\n"
我设法将其向右推,据我所知,但我无法弄清楚正确的推和计数。从这里开始我该怎么做?
addiu
。 - Michael