重复问题
假设我有以下这个颜色:
var c = Color.Red;
现在我想创建一个比这个颜色更浅或更深的新Color
。如何在不太费事的情况下完成这个操作?
重复问题
假设我有以下这个颜色:
var c = Color.Red;
现在我想创建一个比这个颜色更浅或更深的新Color
。如何在不太费事的情况下完成这个操作?
ControlPaint.Light .Dark .DarkDark等。
Color lightRed = ControlPaint.Light( Color.Red );
我最近在博客中谈到了这个问题。主要思路是对每个颜色分量应用一个给定的校正系数。以下静态方法使用指定的校正因子修改给定颜色的亮度,并生成较暗或较亮的变体:
/// <summary>
/// Creates color with corrected brightness.
/// </summary>
/// <param name="color">Color to correct.</param>
/// <param name="correctionFactor">The brightness correction factor. Must be between -1 and 1.
/// Negative values produce darker colors.</param>
/// <returns>
/// Corrected <see cref="Color"/> structure.
/// </returns>
public static Color ChangeColorBrightness(Color color, float correctionFactor)
{
float red = (float)color.R;
float green = (float)color.G;
float blue = (float)color.B;
if (correctionFactor < 0)
{
correctionFactor = 1 + correctionFactor;
red *= correctionFactor;
green *= correctionFactor;
blue *= correctionFactor;
}
else
{
red = (255 - red) * correctionFactor + red;
green = (255 - green) * correctionFactor + green;
blue = (255 - blue) * correctionFactor + blue;
}
return Color.FromArgb(color.A, (int)red, (int)green, (int)blue);
}
n
个浅色调,我该如何使用你的算法? - Geek你也可以使用 Lerp
函数来实现这个功能。XNA 中有一个这样的函数,但是你也可以自己编写。
请参见我在类似问题上的回答以获取 C# 实现。
该函数使您能够执行以下操作:
// make red 50% lighter:
Color.Red.Lerp( Color.White, 0.5 );
// make red 75% darker:
Color.Red.Lerp( Color.Black, 0.75 );
// make white 10% bluer:
Color.White.Lerp( Color.Blue, 0.1 );
public Color Darken(Color color, double darkenAmount) {
HSLColor hslColor = new HSLColor(color);
hslColor.Luminosity *= darkenAmount; // 0 to 1
return hslColor;
}
darkenAmount
参数(我将其命名为 percentage
),让它从颜色到黑或白之间工作。变暗:hslColor.Luminosity *= 1 - percentage;
变亮:hslColor.Luminosity /= 1 - percentage;
。感谢您提供这个出色的答案。 - ctwheels借鉴@Pavel的答案中的核心方法,我为了更直观(至少对于我来说)的签名准备了以下两个小扩展方法。
public static Color LightenBy(this Color color, int percent)
{
return ChangeColorBrightness(color, percent/100.0);
}
public static Color DarkenBy(this Color color, int percent)
{
return ChangeColorBrightness(color, -1 * percent / 100.0);
}
您也可以通过调整RGB百分比来使颜色变浅或变深,以下是如何使颜色比原来暗x%的示例:
//_correctionfactory in percentage, e.g 50 = make it darker 50%
private Color DarkerColor(Color color, float correctionfactory = 50f)
{
const float hundredpercent = 100f;
return Color.FromArgb((int)(((float)color.R / hundredpercent) * correctionfactory),
(int)(((float)color.G / hundredpercent) * correctionfactory), (int)(((float)color.B / hundredpercent) * correctionfactory));
}
另外一个方法是我们可以反向操作,使颜色变得更轻。只需要将255-RGB的结果乘以所需百分比即可,例如以下示例:
private Color LighterColor(Color color, float correctionfactory = 50f)
{
correctionfactory = correctionfactory / 100f;
const float rgb255 = 255f;
return Color.FromArgb((int)((float)color.R + ((rgb255 - (float)color.R) * correctionfactory)), (int)((float)color.G + ((rgb255 - (float)color.G) * correctionfactory)), (int)((float)color.B + ((rgb255 - (float)color.B) * correctionfactory))
);
}
以下是我用于调整颜色明暗度的JavaScript代码。您可以将其作为C#函数的基础。
它的工作原理是计算每个RGB组件与纯白之间的距离,然后通过提供的因子调整此距离。新的距离用于计算新的颜色。因子介于0和1之间时会使颜色变暗,大于1时会使颜色变亮。
function Darken( hexColor, factor )
{
if ( factor < 0 ) factor = 0;
var c = hexColor;
if ( c.substr(0,1) == "#" )
{
c = c.substring(1);
}
if ( c.length == 3 || c.length == 6 )
{
var i = c.length / 3;
var f; // the relative distance from white
var r = parseInt( c.substr(0, i ), 16 );
f = ( factor * r / (256-r) );
r = Math.floor((256 * f) / (f+1));
r = r.toString(16);
if ( r.length == 1 ) r = "0" + r;
var g = parseInt( c.substr(i, i), 16);
f = ( factor * g / (256-g) );
g = Math.floor((256 * f) / (f+1));
g = g.toString(16);
if ( g.length == 1 ) g = "0" + g;
var b = parseInt( c.substr( 2*i, i),16 );
f = ( factor * b / (256-b) );
b = Math.floor((256 * f) / (f+1));
b = b.toString(16);
if ( b.length == 1 ) b = "0" + b;
c = r+g+b;
}
return "#" + c;
}
使用 HSI 转换库(搜索谷歌)。然后,调整 I 通道以获得更浅/更深的颜色。
function lighten(color) {
// convert to decimal and change luminosity
var luminosity = 0.01
var computedColors = new Array();
var newColor = "#",
c, i, n, black = 0,
white = 255;
for (n = 0; n < 10; n++) {
for (i = 0; i < 3; i++) {
c = parseInt(color.substr(i * 2, 2), 16);
c = Math.round(Math.min(Math.max(black, c + (luminosity * white)), white)).toString(16);
newColor += ("00" + c).substr(c.length);
}
computedColors[n] = newColor;
var arrayUnique = checkIfArrayIsUnique(computedColors);
if (arrayUnique == false) {
computedColors.pop();
break;
}
computedColors[n] = newColor;
newColor = "#";
luminosity += calcPercentage();
}
return computedColors;
}
这段代码的作用是接收一个十六进制颜色值,然后输出其10个最浅的颜色版本,并将它们放入数组中。您可以更改亮度以调整阴影百分比。要使颜色变暗,只需更改以下内容:luminosity -= calcPercentage();
我修改了Pavel Vladov的函数来修改即使是RGB成分,以获得任何R/G/B方向组合的阴影:
Public Function ChangeColorShades(color As Color, correctionFactor As Single, bR As Boolean, bG As Boolean, bB As Boolean) As Color
Dim red As Single = CSng(color.R)
Dim green As Single = CSng(color.G)
Dim blue As Single = CSng(color.B)
If (correctionFactor < 0) Then
correctionFactor = 1 + correctionFactor
If bR Then
red *= correctionFactor
End If
If bG Then
green *= correctionFactor
End If
If bB Then
blue *= correctionFactor
End If
Else
If bR Then
red = (255 - red) * correctionFactor + red
End If
If bG Then
green = (255 - green) * correctionFactor + green
End If
If bB Then
blue = (255 - blue) * correctionFactor + blue
End If
End If
Return color.FromArgb(color.A, CInt(red), CInt(green), CInt(blue))
End Function