logo标签列表

如何在Kotlin中获取Drawable？

androidkotlindrawableandroid-resources
6

我正在使用Android Studio进行一个小项目的开发。

我已经将可绘制资源添加到了res/drawable文件夹中。

在此输入图片描述

但是我无法从代码中获取它。我尝试了不同的方法：

ContextCompat.getDrawable(getActivity(), R.drawable.ic_training);

并且

val drawable: Drawable? = ContextCompat.getDrawable(context.applicationContext, R.drawable.ic_training )
val drawable2: Drawable = R.drawable.ic_training

两者都返回错误未解决的引用。 这是我的 XML 文件：

<vector
        android:id = "@+id/ic_training"
        android:alpha="0.85" android:height="24dp"
    android:viewportHeight="24.0" android:viewportWidth="24.0"
    android:width="24dp" xmlns:android="http://schemas.android.com/apk/res/android"
    android:name="ic_training"    >
    <path android:fillColor="#FF000000" android:pathData="M22,21c-1.11,0 -1.73,-0.37 -2.18,-0.64 -0.37,-0.22 -0.6,-0.36 -1.15,-0.36 -0.56,0 -0.78,0.13 -1.15,0.36 -0.46,0.27 -1.07,0.64 -2.18,0.64s-1.73,-0.37 -2.18,-0.64c-0.37,-0.22 -0.6,-0.36 -1.15,-0.36 -0.56,0 -0.78,0.13 -1.15,0.36 -0.46,0.27 -1.08,0.64 -2.19,0.64 -1.11,0 -1.73,-0.37 -2.18,-0.64 -0.37,-0.23 -0.6,-0.36 -1.15,-0.36s-0.78,0.13 -1.15,0.36c-0.46,0.27 -1.08,0.64 -2.19,0.64v-2c0.56,0 0.78,-0.13 1.15,-0.36 0.46,-0.27 1.08,-0.64 2.19,-0.64s1.73,0.37 2.18,0.64c0.37,0.23 0.59,0.36 1.15,0.36 0.56,0 0.78,-0.13 1.15,-0.36 0.46,-0.27 1.08,-0.64 2.19,-0.64 1.11,0 1.73,0.37 2.18,0.64 0.37,0.22 0.6,0.36 1.15,0.36s0.78,-0.13 1.15,-0.36c0.45,-0.27 1.07,-0.64 2.18,-0.64s1.73,0.37 2.18,0.64c0.37,0.23 0.59,0.36 1.15,0.36v2zM22,16.5c-1.11,0 -1.73,-0.37 -2.18,-0.64 -0.37,-0.22 -0.6,-0.36 -1.15,-0.36 -0.56,0 -0.78,0.13 -1.15,0.36 -0.45,0.27 -1.07,0.64 -2.18,0.64s-1.73,-0.37 -2.18,-0.64c-0.37,-0.22 -0.6,-0.36 -1.15,-0.36 -0.56,0 -0.78,0.13 -1.15,0.36 -0.45,0.27 -1.07,0.64 -2.18,0.64s-1.73,-0.37 -2.18,-0.64c-0.37,-0.22 -0.6,-0.36 -1.15,-0.36s-0.78,0.13 -1.15,0.36c-0.47,0.27 -1.09,0.64 -2.2,0.64v-2c0.56,0 0.78,-0.13 1.15,-0.36 0.45,-0.27 1.07,-0.64 2.18,-0.64s1.73,0.37 2.18,0.64c0.37,0.22 0.6,0.36 1.15,0.36 0.56,0 0.78,-0.13 1.15,-0.36 0.45,-0.27 1.07,-0.64 2.18,-0.64s1.73,0.37 2.18,0.64c0.37,0.22 0.6,0.36 1.15,0.36s0.78,-0.13 1.15,-0.36c0.45,-0.27 1.07,-0.64 2.18,-0.64s1.73,0.37 2.18,0.64c0.37,0.22 0.6,0.36 1.15,0.36v2zM8.67,12c0.56,0 0.78,-0.13 1.15,-0.36 0.46,-0.27 1.08,-0.64 2.19,-0.64 1.11,0 1.73,0.37 2.18,0.64 0.37,0.22 0.6,0.36 1.15,0.36s0.78,-0.13 1.15,-0.36c0.12,-0.07 0.26,-0.15 0.41,-0.23L10.48,5C8.93,3.45 7.5,2.99 5,3v2.5c1.82,-0.01 2.89,0.39 4,1.5l1,1 -3.25,3.25c0.31,0.12 0.56,0.27 0.77,0.39 0.37,0.23 0.59,0.36 1.15,0.36z"/>
    <path android:fillColor="#FF000000" android:pathData="M16.5,5.5m-2.5,0a2.5,2.5 0,1 1,5 0a2.5,2.5 0,1 1,-5 0"/>
</vector>
请问您能否检查一下您的drawable文件是否在drawable文件夹中，或者被放错到其他文件夹了吗？ - Afzal Khan
检查它是否在drawable而不是带有任何修饰符的drawable-v24和任何其他文件夹中。 - Arrowsome
可绘制对象的名称是根据其所在的文件命名的，而不是根据 android:id 元素命名的。 - Tenfour04
请在您的问题中[编辑]加入完整的错误信息。这个错误只在编辑器中显示，还是在构建项目时也会出现？ - Code-Apprentice
请查看此链接 https://dev59.com/dm445IYBdhLWcg3wg6tm#71966649 - Mori
5个回答
10

Android SDK 30

ContextCompat.getDrawable(this, R.drawable.name)
在我的情况下，this没有上下文，这正是我提出这个问题的重点。 - Eduardo Reis
6

首先，检查可绘制对象是否在根可绘制对象中，而不是在xxx或其他地方

  • 同样，从矢量形状中删除ID

在您的活动中执行

val drawble = resources.getDrawable(R.drawable.ic_training,theme)

如果在Fragment中。
val drawble = context!!.resources.getDrawable(R.drawable.ic_training,context!!.theme)
1
未解决的引用：资源 - MojioMS
2
resources.getDrawable()已被弃用。 - Greelings
3
2

resources.getDrawable(R.drawable.ic_training, theme)已经被弃用 请使用以下方式

ContextCompat.getDrawable(getActivity(), R.drawable.name)
谢谢兄弟！如此简短而简单 <3 - Nghien Nghien
0

在这里没有看到过这个，但这是对我有效的方法：

   var myShape = ContextCompat.getDrawable(
      applicationContext,
      R.drawable.shape_rectangle  //<-- name of xml file in res folder
   )
网页内容由stack overflow 提供, 点击上面的
可以查看英文原文，
原文链接