我希望在模型的查询集中仅选择几个字段。我看到了这个链接:Django queryset only,我认为我已经实现它了,但我仍然得到整个查询集。
这是我的项目view.py:
from django.shortcuts import get_object_or_404, render
from django.http import HttpResponseRedirect
from django.core.urlresolvers import reverse
from django.views import generic
from django.utils import timezone
from .models import Project
# Create your views here.
class IndexView(generic.ListView):
model = Project.objects.only("name","jobNumber", "contractor", "assigned_to", "created_date")
template_name = 'project/index.html'
def get_queryset(self):
#return Project.objects.all()
return Project.objects.only("name","jobNumber", "contractor", "assigned_to", "created_date")
class DetailView(generic.DetailView):
model = Project
template_name = 'project/detail.html'
这是我的index.html模板。
{% load render_table from django_tables2 %}
{% block content %}
<h1>Projects</h1>
<ul>
{% for project in project_list %}
<li><a href="{% url 'project:detail' project.id %}">{{ project.name }}</a></li>
{% endfor %}
</ul>
{% render_table project_list %}
{% endblock %}
上面的代码给出了 Project 模型中的所有字段。我该如何仅选择一些字段作为 Projects 的输出?任何帮助将不胜感激。