如果我正在遍历一个字典,并且想要获取一个进度条,我应该如何使用tqdm来实现这一点? 我正在使用Python 2.7。
这对于列表非常有效:
for i in tdqm(l, len(l):
<do stuff>
但在字典上失败:
for k, v in tqdm(d.items(), len(d)):
<do stuff>
用字典的正确方法是什么?
这里有一个真实的例子:
d = {'k1':1, 'k2':2}
for k, v in tqdm(d.items(), len(d)):
print 'foo'
a = 1 + 100
print 'bar'
我理解为:
-------------------------------------------------------------------
TypeError Traceback (most recent call last)
<ipython-input-30-7e4ce2b85414> in <module>()
1 d = {'k1':1, 'k2':2}
----> 2 for k, v in tqdm(d.items(), len(d)):
3 print 'oasdlkfj'
4 a = 1 + 100
5 print 'y'
/home/monica/anaconda2/envs/pytorch_p27/lib/python2.7/site-packages/tqdm/_tqdm.pyc in __init__(self, iterable, desc, total, leave, file, ncols, mininterval, maxinterval, miniters, ascii, disable, unit, unit_scale, dynamic_ncols, smoothing, bar_format, initial, position, postfix, unit_divisor, gui, **kwargs)
810 if self.pos:
811 self.moveto(self.pos)
--> 812 self.sp(self.__repr__(elapsed=0))
813 if self.pos:
814 self.moveto(-self.pos)
/home/monica/anaconda2/envs/pytorch_p27/lib/python2.7/site-packages/tqdm/_tqdm.pyc in __repr__(self, elapsed)
842 self.desc, self.ascii, self.unit,
843 self.unit_scale, 1 / self.avg_time if self.avg_time else None,
--> 844 self.bar_format, self.postfix, self.unit_divisor)
845
846 def __lt__(self, other):
/home/monica/anaconda2/envs/pytorch_p27/lib/python2.7/site-packages/tqdm/_tqdm.pyc in format_meter(n, total, elapsed, ncols, prefix, ascii, unit, unit_scale, rate, bar_format, postfix, unit_divisor)
288 if prefix:
289 # old prefix setup work around
--> 290 bool_prefix_colon_already = (prefix[-2:] == ": ")
291 l_bar = prefix if bool_prefix_colon_already else prefix + ": "
292 else:
TypeError: 'int' object has no attribute '__getitem__'